F(x)=sqrt(x)
D(x)=sqrt((f(x)-0)^2+(x-4)^2) [distance of (4,0) from any point on graph]
=sqrt((√x-0)^2+(x-4)^2)
=sqrt(x+(x-4)^2)
To minimize distance, we equate D'(x)=0, or equivalently, we equate the derivative of D(x)^2 to zero.
The latter is easier to derive, and gives the same results.
We will do both.
D'(x)=(1/2)(2(x-4)+1)/sqrt(x+(x-4)^2) [using chain rule]
D'(x)=0 => (2(x-4)+1)=0 => x-4=-1/2 => x=7/2
d(D²(x))/dx
=d(x+(x-4)^2)/dx
=2(x-4)+1
=> 2(x-4)+1=0 => x=7/2
So the point on the graph is (sqrt(7/2),7/2)=(1.8708,3.5) approx.
Answer:
44
Step-by-step explanation:
I had that question before
Answer:
80
Step-by-step explanation:
2400/30=80.
Answer:
111x + 3 - 6
subtract like terms (3 - 6= -3)
111x-3
divide (111x/111 - 3/111)
x - 1/37
