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juin [17]
3 years ago
11

A group of 6 friends went to a basketball tournament game. They each bought a

Mathematics
1 answer:
madam [21]3 years ago
7 0

Answer:44444

Step-by-step explanation:

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It would be y=x+3 because you have a slope of 1 and a y-intercept at 3
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What is the fewest number of expressions that a equation can contain?
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The fewest number of expressions is 3.
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Identify the real number that corresponds to the point plotted on the real number line.
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The real number would be 1.5 or 3/2 or 1 1/2
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4 years ago
Write a percent porportion and solve each number the numbers are 22 is 44% of what number?
Irina-Kira [14]

Answer:

The number is 50.

Step-by-step explanation:

If we express the percentage x% in the form of ratio then it can be written as \frac{x}{100}.

Now, it is asked which number if we make 44 % will give 22.

Let the number is given by x.

Then expressing the % as ratio we can write \frac{22}{x} = \frac{44}{100}

⇒ x=\frac{22 \times 100}{44} = 50 ( Answer )

6 0
4 years ago
Jeanne babysits for $6 per hour. She also works as a reading tutor for $10 per hour. She is only allowed to work 20 hours per we
Maru [420]
A) System of inequalities

Income from babysitting: 6x
Income from tutoring: 10y

Goal for this week: at least $ 75 => 6x + 10y ≥ 75
Number of hours: maximum $20 => x + y ≤ 20

x and y have to be zero or positvie => x≥0 and y ≥ 0

Answer of part A.

6x + 10y ≥ 75
x+y ≤ 20
x ≥ 0
y ≥ 0

Part B. Graph

The solution is a region closed by 4 lines and you can find it in the file attached.

In that graph:

1) the line x + y = 20 is the upper limit
2) the line 6x + 10 y = 75 is the lower incclined line
3) y = 0 is the botton horizontal line it is the x-axis
4) x = 0 is the left vertical line, in is the y-axis

Part C.

Use, for example the point (7,10).

It is in the region of the graph limited by the above equations.

It implies:

Number of hours worked = 7 + 10 = 17 which is less than 20.

Income: 6(7) + 10(10) = 42 + 100 = 142, which is greater than 75

Of course, both are greater than 0.

In this way we proved that the point (7,10) is a true solution for the model.






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8 0
3 years ago
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