3 years ago

What is the fewest number of expressions that a equation can contain?

Mathematics

2 answers:

nlexa [21]3 years ago

8 0

The fewest number of expressions is 3.

umka2103 [35]3 years ago

6 0

The fewest of expression is 4

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I NEED HELP ASAP!!!!!! 20 POINTS. Jake and Finn both worked hard over the summer. Together they earned a total of $400. Finn ear

Semenov [28]

Answer:

225 for finn jake gets 175

Step-by-step explanation:

400 divided by 2 = 200+25 witch gives Finn 225 dollars.

J=175 f=225

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3 years ago

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Work out the size of angle x please!

julia-pushkina [17]

Answer:

x=13

Step-by-step explanation:

one angle of triangle=85

parallel lines and vertical angles

the second angle is 82:

sum of angles of the triangle=180

x+85+82=180

x+167=180

x=180-167

x=13

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3 years ago

What is 200 times 180

Citrus2011 [14]

Hi there! 200 * 180 is 36,000. You can solve this problem by crossing out the 0's, bringing the down, and multiply 18 * 2 to get 36. The product is 36,000.

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3 years ago

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In the diagram below, is circumscribed about quadrilateral ABCD . What is the value of ?

Olin [163]

Answer:

Step-by-step explanation:

There's a property of cyclis quadrilaterals that say that opposite sides will add up to 180

so we have

$5x+75=180\\\\5x=180-75\\\\5x=105\\\\x=21$

which is option c

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3 years ago

18 POINTS! At the AoPS office, mice vary inversely with cats, that is, mice=k/cats, for some value of k. When there are 3r-19 ca

Blizzard [7]

Answer:

k=30

Step-by-step explanation:

The number of mice vary inversely with cats. This is written as:

$Mice \propto \dfrac{1}{Cat} \\Mice = \dfrac{k}{Cat}$

When there are 3r-19 cats, there are 2r+1 mice

$2r+1 = \dfrac{k}{3r-19}\\$Cross multiply$\\k=(3r-19)(2r+1)$

When there are 6r-27 mice, there are r-5 cats.

$6r-27 = \dfrac{k}{r-5}\\$Cross multiply$\\k=(6r-27)(r-5)$

Taking the values of k above, we have:

$k=(3r-19)(2r+1) =(6r-27)(r-5)\\(3r-19)(2r+1) =(6r-27)(r-5)\\6r^2+3r-38r-19=6r^2-30r-27r+135\\$Collect like terms\\6r^2-6r^2+3r+30r-38r+27r-19-135=0\\22r-154=0\\22r=154\\$Divide both sides by 22\\r=7$

Therefore:

$k=(3r-19)(2r+1) \\=(3*7-19)(2*7+1)\\=(21-19)(14+1)\\=2*15\\k=30$

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3 years ago