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3 years ago

1/3s+1/5 how do you do that problem

Mathematics

2 answers:

valentina_108 [34]3 years ago

8 0

Answer:

8/15

Step-by-step explanation:

First you have to make 1/3 and 1/5 common denominators, the LCM is 15 so you would add 5/15 and 3/15 which would give you 8/15.

Hope that helps!

yan [13]3 years ago

8 0

Answer:

8/5

Step-by-step explanation:

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An automobile manufacturer claims that its jeep has a 53.9 miles/gallon (MPG) rating. An independent testing firm has been contr

Advocard [28]

Answer:

Value of the test statistic, $z_{test} = - 1.17$

Step-by-step explanation:

Null hypothesis, $H_{0}: \mu = 53.9$

Alternative hypothesis, $H_{a} : \mu \neq 53.9$

Sample mean, $\bar{X} = 53.7$

Sample size, n = 110

Standard deviation, $\sigma = 1.8$

Significance level, $\alpha = 0.02$

The value of the test statistics is given by the formula:

$z_{test} = \frac{\bar{X} - \mu}{\frac{\sigma}{\sqrt{n} } } \\z_{test} = \frac{53.7 - 53.9}{\frac{1.8}{\sqrt{110} } } \\z_{test} = - 1.17$

7 0

2 years ago

What value of M gives the system infinitely many solutions? -x+2y=16<br> Y=mx+8

Naya [18.7K]

First you move. -x for +x
2y = 16 + x
y = 8 + 1/2 x

the answer is

y = 1/2x + 8

4 0

2 years ago

64, –48, 36, –27, ...<br><br> Which formula can be used to describe the sequence?

nordsb [41]

Answer:

$\boxed{a_n \: = \: 64 \: \times \: ( - \frac{3}{4} ) ^{n \: - \: 1} }$

Step-by-step explanation:

We first compute the ratio of this geometric sequence.

$r \: = \: \frac{ - 48}{64} \\ \\ r \: = \: \frac{36}{ - 48} \\ \\ r \: = \: \frac{ - 27}{36}$

We simplify the fractions:

$r \: = \: - \frac{3 }{4} \\ \\ r \: = \: - \frac{3 }{4} \\ \\ r \: = \: - \frac{3 }{4}$

We deduce that it is the common ratio because it is the same between each pair.

$r \: = \: - \frac{3 }{4}$

We use the first term and the common ratio to describe the equation:

$a_1 \: = \: 64; \: r \: = \: - \frac{3 }{4}$

<h3>We apply the data in this formula:</h3>

$\boxed{a_n \: = \: a_1 \: \times \: {r}^{ n \: - \: 1} }$

_______________________

<h3>We apply:</h3>

$\boxed {\bold{a_n \: = \: 64 \: \times \: {( - \frac{3}{4} )}^{ n \: - \: 1} }}$

<u>Data</u>: The unknown "n" is the term you want

<h3><em><u>MissSpanish</u></em></h3>

4 0

1 year ago

A picture has an area of 35cm and is 7cm long.An enlargement of the picture is made is 21cm long.Find the area of the enlargemen

marta [7]

Answer: The area of the enlargement is 315cm.

Step-by-step explanation:

If the picture has 35cm as the area and it has a length of 7cm then we can find the width by dividing the area by the length.

w= 35/7

w = 5

So in this care the width of the picture in 5cm.

Now is saying that the picture's length has been enlarge or been dilated to 21 cm. To get from 7cm to 21cm you will have to multiply by 3.

In this situation, we will have to multiply the original picture's width by 3 to find it enlargement.

w= 5*3 = 15

The width is 15cm and the length is 21cm so multiply them to find the area.

A = 15 * 21

A = 315cm

6 0

2 years ago

What are the solutions to the equation (x+5)2=32 ?

Vsevolod [243]

Answer:

x = 11

Step-by-step explanation:

(x+5)2 = 32

2x + 10 = 32

2x = 32 - 10

2x = 22

x = 11

8 0

2 years ago

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