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Scilla [17]
3 years ago
7

Elimination Problem Please I Need HELP this makes me want to die lol

Mathematics
1 answer:
Dominik [7]3 years ago
4 0

Answer:

(-3, 4)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients
  • Coordinates (x, y)
  • Solving systems of equation using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

3y = -5x - 3

y = -x + 1

<u>Step 2: Rewrite Systems</u>

Equation y = -x + 1

  1. [Multiplication Property of Equality] Multiply everything by -3:                   -3y = 3x - 3

<u>Step 3: Redefine Systems</u>

3y = -5x - 3

-3y = 3x - 3

<u>Step 4: Solve for </u><em><u>x</u></em>

<em>Elimination</em>

  1. Combine 2 equations:                                                                                   0 = -2x - 6
  2. [Addition Property of Equality] Add 6 on both sides:                                  6 = -2x
  3. [Division Property of Equality] Divide -2 on both sides:                              -3 = x

<u>Step 5: Solve for </u><em><u>y</u></em>

  1. Define original equation:                                                                               y = -x + 1
  2. Substitute in <em>x</em>:                                                                                                y = -(-3) + 1
  3. Simplify:                                                                                                           y = 3 + 1
  4. Add:                                                                                                                 y = 4
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Determine the length of the base and the corresponding height of ABC, and use them to find the area of ABC.
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The area of the triangle is 30 units^2. the height of the triangle is 4 units.

<h3>What is the area of the triangle?</h3>

The area of the triangle is defined as the product of half the base and the height of the triangle.

The area of the triangle can be calulated by the herons formula

base of ABC = AC = 15 units

Height of ABC = 4 units

Semi perimeter s = 5 + 12.65 + 15/ 2 = 32.65 / 2 = 16.32

Herons formula

Area = \sqrt{s(s-a) (s-b)(s-c)}\\\\Area = \sqrt{16.32(16.32-5) (16.32-12.65)(16.32-15)}\\\\Area = \sqrt{16.32(11.32) (3.675)(1.32)}\\\\Area = 29.93

Area of ABC is 30 units^2 approximately.

Height of the triangle = 2( area) / base

                                    = 2( 30) / 15

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WE can see that

Area of ABC = 1/2 (base) (height)

                     = 1/2 (15 units) (4 units)

                      = 30 units^2

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<u>Step-by-step explanation:</u>

Use the exponential growth formula   y = a(b)ˣ     where

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  • b = 1 + r  (for growth) or 1 - r for decay
  • r = rate (convert percent to a decimal)

a)    Given: a = 250,    r = 80% (.80) → b = 1.8

       y = 250(1.8)ˣ

b)  Given: x = 10

     y = 250(1.8)¹⁰

     y = 89,261.68   =  89,262 (rounded to the nearest whole number)

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A 20 inch tall plant grows 4 inches per month. What would be the height of the plant after 10
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Step-by-step explanation:

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Translate the algebraic expression and simplify if possible.
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Four boys weighed themselves in different pairs and alone. The weights of the pairs were 110 kg, 112 kg, 113 kg, 118 kg, 121 kg,
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The lost pair of weight can be found by subtracting the a known pair from

the total weight leaving the value of the lost pair.

<u>The lost weight of a pair of boys is 120 kg</u>

Reasons:

Let <em>a</em>, <em>b</em>, <em>c</em>, and <em>d</em><em> </em>represent the weights of the four boys, we have;

The number of ways of selecting pairs (two boys) of boys from a group of

four is given using combination formula as follows;

_nC_r = \dfrac{n!}{r! \cdot (n - r)!}

Which gives;

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₄C₂ = 6

Therefore, the weights of the pairs are;

a + b = 110

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b + c = 118

b + d = 121

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a + b + c + d = 230 (given)

Therefore;

The lost weight, c + d = 230 - (a + b)

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The lost weight = c + d = 120

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