<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
Answer:
Coronal Plane
Explanation:
It is also known as Y-X plane or Frontal planes; the coronal plane divides the body into ventral (front) and dorsal (back) portions.
Mitosis consists of four basic phases:
<em>prophase, metaphase, anaphase, and telophase</em>. Some textbooks list five, breaking prophase into an early phase (called prophase) and a late phase (called prometaphase). These phases occur in strict sequential order, and
<em>cytokinesis</em> - the process of dividing the cell contents to make two new cells -
<em>starts in anaphase or telophase</em>.
I gave you a diagram to help put these words into an image.
I hope this helped!!! Have a wonderful day ! :))
