Answer:
Step-by-step explanation:
Sum of interior angle of any polygon = 180* (n- 2 )
Here, n= number of sides
Sum of interior angles of regular octagon = 180 * ( 8-2) = 180 * 6 = 1080°
In regular octagon, all the angles are congruent,
So, measure of an interior angle of regular octagon = 1080/8 = 135°
Sum of interior angles of regular hexagon = 180 * ( 6-2) = 180*4 = 720°
In regular hexagon, all the angles are congruent,
So, measure of an interior angle of regular hexagon = 720/6 = 120°
The measure of an interior angle of a regular octagon is greater than the measure of an interior angle of a regular hexagon by 15°
Answer:
1) 22.5 A
2) 112 B
3) 430 L
4) 576 P
5) 486 L
6) 624 S
Code is A B L P L S
Step-by-step explanation:
1) Area of a triangle = 1/2 * base * height = 1/2 *5*9 = 22.5
2) Area of a parallelogram = base x height = 14 x 8 = 112
3) Area of a rectangular prism = 2(length * width) + 2*(length + height) + 2 *(length *height)
= 2(15x7 + 15*5 + 7*5)
= 2(105 + 75 + 35)
= 2 * 215
= 430
4) Volume of a triangular prism = 1/2 * base * length * height
= 1/2 * 8 * 16 * 9
= 576
5) A cube has six surfaces. Each surface has an area of s x s where s is the length of each side. In this case, each side has area of 9x9 = 81. Total surface area = 6 x 81 = 486 and that is the paper required
6) The trailer is a rectangular prism so its volume = length x width x height = 13 6 x 8 = 624
Now you have to look at each value and see which letter it corresponds to. For example answer 1) is 22.5 which lies between 0-100 so it gets letter A, answer (2) is 112 which lies in the range 101-200 so it gets the letter B and so on
For the first is 3864
The second is 1320
A=3.14(which is pie) x 20.5^2
A=420x pie
A=1320
For the third is 2544
3864-1320=2544
Sorry if this is wrong too.
Answer:
4_5=_1 then -1 is <25 25_1 25<-1
Triangle ABE is isosceles / Given
AB congruent to AE / Def isosceles
angle ABE congruent to angle AEB / Property of isosceles triangles
angle ABD congruent to angle AEC / Subst different name for same angles
BD congruent to EC / Given
triange ABD congruent to triange AEC / Side Angle Side