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Rama09 [41]
3 years ago
15

30 POINTS PLEASE HELP ASAP!!!

Mathematics
1 answer:
7nadin3 [17]3 years ago
6 0

It's the fourth option, 1 - sin<em>θ</em>/csc<em>θ</em>. This is due to the cancellation of cos<em>θ</em> in the numerator:

1 - (sin<em>θ</em>/cos<em>θ</em> × cos<em>θ</em>)/csc<em>θ</em> = 1 - sin<em>θ</em>/csc<em>θ</em>

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equation c: y = 6x+9 equation d: y = 6x + 2 how many solutions are there to the given set of equation
bekas [8.4K]
Y=6x+9. y=6x+2. Therefore y=6x+9=6x+2. 6x+9=6x+2. 6x-6x=2-9. 0=-7. This is not true. So this is- No solution
7 0
3 years ago
Find the following sum of the following expressions: 3x+5 and -4x-10
NeTakaya

Answer:

x + 5

Step-by-step explanation:

3x + 5 -4x - 10

Combine like terms.

-x -5

Divide by -1

x + 5

I hope that this helps! :)

6 0
3 years ago
Erick just answered a help-wanted ad. The ad states that the job pays $45K 1 point
Rudiy27

Answer:

Per month salary = $3,750

Step-by-step explanation:

Given:

Annual pay = $45,000

Find:

Per month salary

Computation:

Number of month in a year = 12

Per month salary = Annual pay / Number of month in a year

Per month salary = $45,000 / 12

Per month salary = $3,750

8 0
3 years ago
Express the given integral as the limit of a riemann sum but do not evaluate: the integral from 0 to 3 of the quantity x cubed m
WARRIOR [948]
We will use the right Riemann sum. We can break this integral in two parts.
\int_{0}^{3} (x^3-6x) dx=\int_{0}^{3} x^3 dx-6\int_{0}^{3} x dx
We take the interval and we divide it n times:
\Delta x=\frac{b-a}{n}=\frac{3}{n}
The area of the i-th rectangle in the right Riemann sum is:
A_i=\Delta xf(a+i\Delta x)=\Delta x f(i\Delta x)
For the first part of our integral we have:
A_i=\Delta x(i\Delta x)^3=(\Delta x)^4 i^3
For the second part we have:
A_i=-6\Delta x(i\Delta x)=-6(\Delta x)^2i
We can now put it all together:
\sum_{i=1}^{i=n} [(\Delta x)^4 i^3-6(\Delta x)^2i]\\\sum_{i=1}^{i=n}[ (\frac{3}{n})^4 i^3-6(\frac{3}{n})^2i]\\&#10;\sum_{i=1}^{i=n}(\frac{3}{n})^2i[(\frac{3}{n})^2 i^2-6]
We can also write n-th partial sum:
S_n=(\frac{3}{n})^4\cdot \frac{(n^2+n)^2}{4} -6(\frac{3}{n})^2\cdot \frac{n^2+n}{2}

4 0
4 years ago
Answer the question.<br><br> -5/3 x -3/4
iren2701 [21]

Answer:

5/4 or 1.25

Step-by-step explanation:

-5/3 x -3/4

apply the fraction rule

-5/3 = 5/3

apply the same rule to -3/4

= 5/3 x 3/4

cross cancel common factor which is 3

and you will get 5/4

6 0
3 years ago
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