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Lilit [14]
3 years ago
15

X + y + 2 = 63x - 2y = - 42x - y + = 9

Mathematics
1 answer:
scoundrel [369]3 years ago
7 0

Answer:

this question is not correct

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determine the value of x for which r parallels s. then find the measure of angle 1 and the measure of angle 2measure angle 1= 50
Maslowich

According to the picture, angles 1 and 2 have the same measure because they are corresponding angles. Make equal both expressions for 1 and 2 and find x.

\begin{gathered} 50-2x=110-42x \\ 42x-2x=110-50 \\ 40x=60 \\ x=\frac{60}{40} \\ x=\frac{3}{2} \end{gathered}

x is 3/2. Replace this value in both expression to find the measure of each angle.

\begin{gathered} \measuredangle1=50-2x \\ \measuredangle1=50-2(\frac{3}{2}) \\ \measuredangle1=50-3 \\ \measuredangle1=47 \\ \measuredangle2=110-42x \\ \measuredangle2=110-42(\frac{3}{2}) \\ \measuredangle2=110-63 \\ \measuredangle2=47 \end{gathered}

The measure of these angles is 47°

7 0
1 year ago
Find the slope of two points: (-2,-1) and (4,3)
marta [7]

Answer: m = 2/3

\frac{-1-3}{-2-4} = \frac{-4}{-6} = \frac{2}{3}

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3 years ago
A rectangular prism with length L, width W, and height H has a volume of LHW.
Anika [276]

Answer:There was not enough information given in the drawing and/or given list to prove the statement.

Not enough information.

Step-by-step explanation:

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3 years ago
How do we calculate the rate of change for a given domain
SashulF [63]

Answer:The average rate of change between two input values is the total change of the function values (output values) divided by the change in the input values.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
3 years ago
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