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Anettt [7]
3 years ago
13

Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays

to 356g over 7 days.
Mathematics
1 answer:
katrin2010 [14]3 years ago
7 0

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

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Answer:

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Explanation:

Let x= the age of the youngest child.

If the oldest child is twice the age of the youngest, the age of the oldest child is twice x or 2x.

If the middle child is 3 years older than the youngest, the age of the middle child is x+3.

If the sum of their ages is 27, then

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3 years ago
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Ana purchased a gallon of milk for $2.22, bagels for $2.97, and a box of
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Solution:

The table which is about kind of jeans and it's color is

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loose fit    indigo  

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3 years ago
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Answer:

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