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3 years ago

If x:6 as 3:9, then x is equal to

Mathematics

1 answer:

lana66690 [7]3 years ago

6 0

Answer:

the value of x in simplified form is 2.

Step-by-step explanation:

Given;

x:6 as 3:9

the value of x can be obtained if this ratio is transformed into fraction form.

in fraction form, this ratio can be written as;

$\frac{x}{6} = \frac{3}{9} \\\\simplifying\ this \ equation\ we \ will \ have \ the \ following \ result;\\\\x = \frac{ 6\times 3}{9} \\\\x = \frac{18}{9} \\\\x = 2$

Therefore, the value of x in simplified form is 2.

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the table below represents the displacement of a turtle from its nest as a function of time.Part A. What is the y intercept of t

hoa [83]

Part A.

Y intercept is the coordinate (0,y), when the function has an x value of 0, it is the y intercept.

In this case:

(0,5) =

y intercept = 5

IT tells about the turtle that it starts at a nest displacement of 5 miles.

Part B

The average rate of change represents the speed .

x1=1 ,y1=27

x2=4 ,y2=93

We have to calculate the slope if the function:

$\text{slope}=\text{ }\frac{y2-y1}{x2-x1}$

Replace:

$\text{slope}=\frac{93-27}{4-1}\text{ = }\frac{66}{3}=22$

Part C.

speed = distance /time

time= distance / speed

time= 225 / 22 = 10.22 hours

The domain will be

0< x ≤ 10.22

3 0

1 year ago

Let Z be a standard normal random variable and calculate the following probabilities, drawing pictures wherever appropriate. (Ro

puteri [66]

Answer:

(a) P(0 ≤ Z ≤ 2.87)=0.498

(b) P(0 ≤ Z ≤ 2)=0.477

(d) P(−2.20 ≤ Z ≤ 2.20)=0.972

(e) P(Z ≤ 1.01)=0.844

(f) P(−1.95 ≤ Z)=0.974

(g) P(−1.20 ≤ Z ≤ 2.00)=0.862

(h) P(1.01 ≤ Z ≤ 2.50)=0.150

(i) P(1.20 ≤ Z)=0.115

(j) P(|Z| ≤ 2.50)=0.988

Step-by-step explanation:

(a) P(0 ≤ Z ≤ 2.87)

In this case, this is equal to the difference between P(z<2.87) and P(z<0). The last term is substracting because is the area under the curve that is included in P(z<2.87) but does not correspond because the other condition is that z>0.

$P(0 \leq z \leq 2.87)= P(z$

(b) P(0 ≤ Z ≤ 2)

This is the same case as point a.

$P(0 \leq z \leq 2)= P(z$

This is the same case as point a.

$P(-2.2 \leq z \leq 0)= P(z$

(d) P(−2.20 ≤ Z ≤ 2.20)

This is the same case as point a.

$P(-2.2 \leq z \leq 2.2)= P(z$

(e) P(Z ≤ 1.01)

This can be calculated simply as the area under the curve for z from -infinity to z=1.01.

$P(z\leq1.01)=0.844$

(f) P(−1.95 ≤ Z)

This is best expressed as P(z≥-1.95), and is calculated as the area under the curve that goes from z=-1.95 to infininity.

It also can be calculated, thanks to the symmetry in z=0 of the standard normal distribution, as P(z≥-1.95)=P(z≤1.95).

$P(z\geq -1.95)=0.974$

(g) P(−1.20 ≤ Z ≤ 2.00)

This is the same case as point a.

$P(-1.20 \leq z \leq 2.00)= P(z$

(h) P(1.01 ≤ Z ≤ 2.50)

This is the same case as point a.

$P(1.01 \leq z \leq 2.50)= P(z$

(i) P(1.20 ≤ Z)

This is the same case as point f.

$P(z\geq 1.20)=0.115$

(j) P(|Z| ≤ 2.50)

In this case, the z is expressed in absolute value. If z is positive, it has to be under 2.5. If z is negative, it means it has to be over -2.5. So this probability is translated to P|Z| < 2.50)=P(-2.5<z<2.5) and then solved from there like in point a.

$P(|z|$