Check whether it is possible to have a triangle with the given side lengths for example 7,9,13 then add any two sides and see if it is greater than the other side. Example the sum of 7 and 9 is 16 and 16 is greater than 13
Answer:
Explanation:
05/10
Simplifying
1/2
or 2^-1
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40 is your answer. Because, you need the lowest multiple so we have to find it by making out a chart of their multiples
8, 16,24,32,40
10,20,30,40
The first same multiple they make is 40
Answer:
k = -7
Step-by-step explanation:
Solve for k:
-7 k - 44 = k + 12
Subtract k from both sides:
(-7 k - k) - 44 = (k - k) + 12
-7 k - k = -8 k:
-8 k - 44 = (k - k) + 12
k - k = 0:
-8 k - 44 = 12
Add 44 to both sides:
(44 - 44) - 8 k = 44 + 12
44 - 44 = 0:
-8 k = 12 + 44
12 + 44 = 56:
-8 k = 56
Divide both sides of -8 k = 56 by -8:
(-8 k)/(-8) = 56/(-8)
(-8)/(-8) = 1:
k = 56/(-8)
The gcd of 56 and -8 is 8, so 56/(-8) = (8×7)/(8 (-1)) = 8/8×7/(-1) = 7/(-1):
k = 7/(-1)
Multiply numerator and denominator of 7/(-1) by -1:
Answer: k = -7
