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We have by distributivity of limits over sums, and continuity of 
and 
, that
Given 
, it follows that
Answer:
Amount left in bag one = 20kg
Amount left in bag 2 = 40 kg
Step-by-step explanation:
We are told that Two bags had 50 kilograms of sugar each.
Let first bag be x and second bag be y.
Now, we are told that After taking out 3 times as much sugar from bag one than bag two, bag one had half as much sugar left as bag two.
Thus, amount taken from bag one is;
3a and amount taken from bag two is a.
Amount left in bag 1 is;
50 - 3a while amount left in bag 2 is 50 - a.
Since bag one had half as much sugar left as bag two, then;
50 - 3a = ½(50 - a)
50 - 3a = 25 - 0.5a
50 - 25 = 3a - 0.5a
25 = 2.5a
a = 25/2.5
a = 10
Thus;
Amount left in bag 1 = 50 - 3a = 50 - 3(10) = 50 - 30 = 20 kg.
Amount left in bag 2 = 50 - a = 50 - 10 = 40 kg
