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ahrayia [7]
3 years ago
11

Multiply and Simplify:

Mathematics
1 answer:
myrzilka [38]3 years ago
4 0
The answer is 1. 15a2-19ab-56b2
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El 10% de 2cm cubicos
egoroff_w [7]

Answer:

     

Step-by-step explanation:

6 0
2 years ago
at five pm a four foot mailbox casts a shadow six feet long at the same time a tree cast a shadow 36 feet Long bhow tall is the
Andrej [43]

So the 4ft mailbox’s shadow was six feet. That 2ft longer. According to my logic if the tree had a showdown of 36ft we subtract 2ft. The trees actual size is 34ft.

I might be wrong don’t hate me :(

5 0
2 years ago
How long will it take an airplane flying at an average cruising speed of 230 miles per hour to fly 1380 miles?
lora16 [44]

Since it takes one hour to fly 230 miles, and we are looking for the number of hours, we can divide the number of miles we are given by the speed. In this case, we would divide 1380 by 230 to get 6. This means it would take 6 hours for the plane to fly 1380 miles.

7 0
2 years ago
Which of the following statements could be translated to the equation n-5=-2?
Klio2033 [76]

Answer:

The difference between a number and five is negative two.

Step-by-step explanation:

n-5=difference between a number and five

=-2 means is negative two

8 0
3 years ago
Suppose a normal distribution has a mean of 222 and a standard deviation of 16. What is the probability that a data value is bet
valentina_108 [34]
Mean of the distribution = u = 222
Standard Deviation = s = 16

We have to find the probability that a value lies between 190 and 230.

First we need to convert these data values to z score.

z= \frac{x-u}{s}

For x = 190, 
z= \frac{190-222}{16}=-2

For x = 230
z= \frac{230-222}{16}=0.5

So, we have to find the percentage of values lying between z score of -2 and 0.5

P( -2 < z < 0.5) = P(0.5) - P(-2)

From standard z table, we can find and use these values.

P(-2 < x < 0.5 ) = 0.6915 - 0.0228 = 0.6687

Thus, there is 0.6887 probability that the data value will lie between 190 and 230 for the given distribution. 

5 0
3 years ago
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