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3 years ago

What is the y intercept The graph X Y -2 3 -1 5 0 7 1 9 2 11

Mathematics

1 answer:

Bad White [126]3 years ago

4 0

Answer:

0 7

Step-by-step explanation:

at the Y- intercept the value of x is zero

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kathy plans to bake 2 types of cookies to take to the party. She needs to be sure she has enough ingredients. The chocolate chip

myrzilka [38]

Answer:

4 11/12

I hope I helped! (If I got it wrong, feel free to tell me I got it wrong)

7 0

3 years ago

After a snowstorm in the town of Golden Glen, the morning temperature was – 10°F. But by the afternoon, the temperature had rise

spayn [35]

Answer:

7°F

Step-by-step explanation:

We have the following information from the question;

Morning temperature = -10°F

Increase in temperate = 17°F

Afternoon temperature = the unknown

Since;

Increase in temperature = Afternoon temperature - morning temperature

Then;

Afternoon temperature = increase in temperature + morning temperature

Afternoon temperature = 17°F + (-10°F)

Afternoon temperature= 7°F

5 0

3 years ago

Robert buys a new pair of boots for 120 dollars. Sales tax is

Margarita [4]

Answer: $133.20

Step-by-step explanation: To simply find the sales tax all you have to do is:

Step 1 Multiply: 120 x .11 = 13.2

Step 2 Add: 120 + 13.2 = 132.2

So Robert actually has to pay $133.20

7 0

3 years ago

Calculus 2 Master needed, evaluate the indefinite integral of: <img src="https://tex.z-dn.net/?f=%5Cint%5C%28%20%28lnx%29%5E2%7D

viva [34]

Answer:

$\int (\ln(x))^2dx=x(\ln(x)^2-2\ln(x)+2)+C$

Step-by-step explanation:

So we have the indefinite integral:

$\int (\ln(x))^2dx$

This is the same thing as:

$=\int 1\cdot (\ln(x))^2dx$

So, let's do integration by parts.

Let u be (ln(x))². And let dv be (1)dx. Therefore:

$u=(\ln(x))^2\\\text{Find du. Use the chain rule.}\\\frac{du}{dx}=2(\ln(x))\cdot\frac{1}{x}$

Simplify:

$du=\frac{2\ln(x)}{x}dx$

And:

$dv=(1)dx\\v=x$

Therefore:

$\int (\ln(x))^2dx=x\ln(x)^2-\int(x)(\frac{2\ln(x)}{x})dx$

The x cancel:

$=x\ln(x)^2-\int2\ln(x)dx$

Move the 2 to the front:

$=x\ln(x)^2-2\int\ln(x)dx$

(I'm not exactly sure how you got what you got. Perhaps you differentiated incorrectly?)

Now, let's use integrations by parts again for the integral. Similarly, let's put a 1 in front:

$=x\ln(x)^2-2\int 1\cdot\ln(x)dx$

Let u be ln(x) and let dv be (1)dx. Thus:

$u=\ln(x)\\du=\frac{1}{x}dx$

And:

$dv=(1)dx\\v=x$

So:

$=x\ln(x)^2-2(x\ln(x)-\int (x)\frac{1}{x}dx)$

Simplify the integral:

$=x\ln(x)^2-2(x\ln(x)-\int (1)dx)$

Evaluate:

$=x\ln(x)^2-2(x\ln(x)-x)$

Now, we just have to simplify :)

Distribute the -2:

$=x\ln(x)^2-2x\ln(x)+2x$

And if preferred, we can factor out a x:

$=x(\ln(x)^2-2\ln(x)+2)$

And, of course, don't forget about the constant of integration!

$=x(\ln(x)^2-2\ln(x)+2)+C$

And we are done :)

8 0

3 years ago

The current population of a town is 8,000. If the population, P, increases by 25% each year, which equation could be used to fin

Bad White [126]

Answer:

given:

principal [P]=8000

rate[r]=15%

population after t years=?

we have

population after t years=P(1+r/100)^t=8000(1+15/100)^t is your answer

4 0

2 years ago