The frustum can be considered as consisting of a square pyramid, less the
cut volume.
- The mass of the stand, is approximately 18.60905 kg
Reasons:
The given parameter of the frustum are;
The density of the frustum, ρ = 85 g/cm³
Height of pyramid, h = 9 cm
Side length of base = 10 cm
Height of frustum
By proportional shapes, the side length of the top of the frustum can be found as follows;



B₁ = 10², B₂ = 
Therefore;

The volume of the stand, V ≈ 218.93 cm³
Mass = Volume × Density
∴ Mass of the stand, m = 218.93 cm³ × 85 g/cm³ = 18,609.05 grams = 18.60905 kg.
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Answer:
C. 
Step-by-step explanation:
Given


Required
Equation of line
Let m represents the slope of the line;
m is calculated as thus




By substituting the right values in the formula above;
becomes

Multiply both sides by 





Reorder

Hence, the equation that represents the line is 
Answer:1:3
Step-by-step explanation:
Answer:4/15
Step-by-step explanation:
Change the whole number into a fraction and divide both and you get 4/15 or get photomath with math problems works perfectly
Area = the top semicircle + the rectangle AEBD
= 1/2 pi*6^2 + 6*12 = 128.55 cm^2 to nearest 100th
Perimeter = 6pi + 12 + 2 pi * 3 = 49.70 cm