Solution:
<u>Step-1: Find the slope of the line.</u>
Formula of slope: y₂ - y₁/x₂ - x₁
- y₂ - y₁/x₂ - x₁ = Slope
- => -2 - (-5)/-8 - (-4) = Slope
- => -2 + 5/-8 + 4 = Slope
- => 3/-4 = Slope
<u>Step-2: Use the point slope formula to determine the slope.</u>
Point slope form formula: y - y₁ = m(x - x₁)
- y - y₁ = m(x - x₁) = Equation of line
- => y - (-5) = -3/4{x - (-4)} = Equation of line
- => y + 5 = -3/4{x + 4} = Equation of line
- => y + 5 = -3x/4 - 3 = Equation of line
- => y = -3x/4 - 8 = Equation of line
The equation of the line is <u>y = -3x/4 - 8.</u>
The equation for monthly payment is b = 49.05M.
<u>SOLUTION:</u>
Given, a cellular family phone plan cost $49 per minute plus five cents per minute of long distance service. We have to write an equation for the monthly payment b when M minutes of long distance service are used.
Now, given that,
![\begin{array}{l}{\text { Monthly payment = } \$ 49 \text { per minute plus five cents per minute of long distance }} \\\\ {\Rightarrow \$ 49 \times \text { number of minutes }+\$ 0.05 \times \text { number of minutes of long distance }} \\\\ {\Rightarrow \mathrm{b}=49 \times \mathrm{M}+0.05 \times \mathrm{M} \rightarrow \mathrm{b}=49 \mathrm{M}+0.05 \mathrm{M} \rightarrow \mathrm{b}=49.05 \mathrm{M}}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Ctext%20%7B%20Monthly%20payment%20%3D%20%7D%20%5C%24%2049%20%5Ctext%20%7B%20per%20minute%20plus%20five%20cents%20per%20minute%20of%20long%20distance%20%7D%7D%20%5C%5C%5C%5C%20%7B%5CRightarrow%20%5C%24%2049%20%5Ctimes%20%5Ctext%20%7B%20number%20of%20minutes%20%7D%2B%5C%24%200.05%20%5Ctimes%20%5Ctext%20%7B%20number%20of%20minutes%20of%20long%20distance%20%7D%7D%20%5C%5C%5C%5C%20%7B%5CRightarrow%20%5Cmathrm%7Bb%7D%3D49%20%5Ctimes%20%5Cmathrm%7BM%7D%2B0.05%20%5Ctimes%20%5Cmathrm%7BM%7D%20%5Crightarrow%20%5Cmathrm%7Bb%7D%3D49%20%5Cmathrm%7BM%7D%2B0.05%20%5Cmathrm%7BM%7D%20%5Crightarrow%20%5Cmathrm%7Bb%7D%3D49.05%20%5Cmathrm%7BM%7D%7D%5Cend%7Barray%7D)
<em>Equation:</em>
An equation is a statement that the values of two mathematical expressions are equal <em>(indicated by the sign =)</em>
The answer is B) x^3-1 because it's the only one with the 3rd degree
75. Hope this answer helped Please consider giving me brainlist
Answer:
![(a)\ -16t^2 + 7t + 63=0](https://tex.z-dn.net/?f=%28a%29%5C%20-16t%5E2%20%2B%207t%20%2B%2063%3D0)
![(b)\ t = 2.215](https://tex.z-dn.net/?f=%28b%29%5C%20t%20%3D%202.215)
Step-by-step explanation:
Given
![h(t) = -16t^2 + 7t + 63](https://tex.z-dn.net/?f=h%28t%29%20%3D%20-16t%5E2%20%2B%207t%20%2B%2063)
Solving (a): Equation when it hits the ground.
This means that ![h(t) = 0](https://tex.z-dn.net/?f=h%28t%29%20%3D%200)
So, we have:
![h(t) = -16t^2 + 7t + 63](https://tex.z-dn.net/?f=h%28t%29%20%3D%20-16t%5E2%20%2B%207t%20%2B%2063)
![-16t^2 + 7t + 63=0](https://tex.z-dn.net/?f=-16t%5E2%20%2B%207t%20%2B%2063%3D0)
Solving (b): The value of t in (a)
![-16t^2 + 7t + 63=0](https://tex.z-dn.net/?f=-16t%5E2%20%2B%207t%20%2B%2063%3D0)
Using quadratic formula, we have:
![t = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-b%20%5C%C2%B1%20%5Csqrt%7Bb%5E2%20-%204ac%7D%7D%7B2a%7D)
This gives:
![t = \frac{-7 \± \sqrt{7^2 - 4*-16*63}}{2*-16}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-7%20%5C%C2%B1%20%5Csqrt%7B7%5E2%20-%204%2A-16%2A63%7D%7D%7B2%2A-16%7D)
![t = \frac{-7 \± \sqrt{49+ 4032}}{2*-16}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-7%20%5C%C2%B1%20%5Csqrt%7B49%2B%204032%7D%7D%7B2%2A-16%7D)
![t = \frac{-7 \± \sqrt{4081}}{-32}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-7%20%5C%C2%B1%20%5Csqrt%7B4081%7D%7D%7B-32%7D)
![t = \frac{-7 \± 63.88}{-32}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-7%20%5C%C2%B1%2063.88%7D%7B-32%7D)
Split
![t = \frac{-7 + 63.88}{-32}; or\ t = \frac{-7 - 63.88}{-32}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-7%20%2B%2063.88%7D%7B-32%7D%3B%20or%5C%20t%20%3D%20%5Cfrac%7B-7%20-%2063.88%7D%7B-32%7D)
![t = \frac{56.88}{-32}; or\ t = \frac{-70.88}{-32}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B56.88%7D%7B-32%7D%3B%20or%5C%20t%20%3D%20%5Cfrac%7B-70.88%7D%7B-32%7D)
![t = -1.7775; or\ t = 2.215](https://tex.z-dn.net/?f=t%20%3D%20-1.7775%3B%20or%5C%20t%20%3D%202.215)
Time can't be negative; So:
![t = 2.215](https://tex.z-dn.net/?f=t%20%3D%202.215)