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3 years ago

Find the differential of the function. z = e−4x cos(4πt)

Mathematics

1 answer:

Goryan [66]3 years ago

3 0

(dz/dx)= (-e+4)(4pi)sin(4pi*t)

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(-3,-2). (9. -15)<br> Slope

zaharov [31]

answer:

-13/12

Step-by-step explanation:

use the formula to find slope using points

it is: y2-y1/x2-x1

plug in point values into formula

-3 = x1. 9 = x2

-2= y1. -15 = y2

-15-(-2)/ 9-(-3)

-13/12

4 0

2 years ago

Read 2 more answers

Explain how 9 x 4 can help you find 9 x 8

MrMuchimi

You can double the product of 9 and 4 to get to the product of 9 and 8

3 0

2 years ago

Read 2 more answers

The diagonal of a rectangle is 25 in. The width is 15 in. What is the area of the rectangle

djyliett [7]

Here is your answer > >

Width of rectangle =15 inches

Length of rectangle =?

Diagonal of rectangle = 25 inches

We know that

(Diagonal of rectagle)^2=length^2+breadth^2

(25)^2=l^2+(15)^2

625=l^2+225

l^2=625-225

l^2=400

l=Root 400

l=20 inches

Hope it helps!

Thankyou ☆ ☆

Bebrainly

6 0

2 years ago

The perimeter of a rectangle is 34 units. Its width is 6.5 point, 5 units.

12345 [234]

<h3><u>Question:</u></h3>

The perimeter of a rectangle is 34 units. Its width W is 6.5 units.

Write an equation to represent the perimeter in terms of the length L, and find the value of L

<h3><u>Answer:</u></h3>

The length of rectangle is 10.5 units

<h3><u>Solution:</u></h3>

Given that,

Perimeter of rectangle = 34 units

Width of rectangle = 6.5 units

Let "L" be the length of rectangle

<em><u>The perimeter of rectangle is given by formula:</u></em>

Perimeter = 2(length + width)

<em><u>Substituting the values we get,</u></em>

$34 = 2(L + 6.5)$

Thus the equation is found

<em><u>Solve for "L"</u></em>

$L + 6.5 = \frac{34}{2}\\\\L + 6.5 = 17\\\\L = 17 - 6.5\\\\L =10.5$

Thus length of rectangle is 10.5 units

6 0

3 years ago

Application of Geometric Series

Gnoma [55]

Answer:

7.2224

Step-by-step explanation:

The value of the summation is given by the formula ...

Sn = (a1)(1 -r^n)/(1 -r) . . . . . where a1 is the first of n terms, and r is the common ratio.

Your sum has first term and ratio ...

a1 = 2(0.6) . . . . . summation term for n=1

r = 0.6

So the sum is ...

$\displaystyle \sum_{n=1}^4{2(0.6^n)}=2(0.6)\dfrac{1-0.6^4}{1-0.6}=\dfrac{1.2}{0.4}(0.8704) = 2.6112$

Then the value of the entire given expression is ...

$\displaystyle 2+2\sum_{n=1}^4{}2(0.6^n)=2+2(2.6112)=\boxed{7.2224}$

_____

A calculator can help you find the value.

6 0

1 year ago