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Tpy6a [65]
3 years ago
6

Solve 5x/3 + 2/5 = 1 x = 9/25 x= 25/9 x= 3/25 x = 9/27

Mathematics
1 answer:
musickatia [10]3 years ago
8 0

Answer:

x=\frac{9}{25}

x = 0.36

Step-by-step explanation:

5x/3 + 2/5 = 1

5x/3 + 2/5 - 2/5 = 1 - 2/5

\frac{5x}{3}  = 0.6

5x/3 × 3 = 0.6 × 3

5x = 1.8

5x ÷ 5 = 1.8 ÷ 5

x=\frac{9}{25}

x = 0.36

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Total weight of the apples:
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3 + 4.2 = 7.2

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Cost of the apples:
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7.2 x 1.75 = $12.60

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Answer: Harold spent $12.60.
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8 0
4 years ago
In the diagram AB bisects FAE. BF=5x and BE=x2+6. Solve for x.
Lilit [14]
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5 0
3 years ago
The midpoint of AB is M(-5,1). If the coordinates of A are (-4,-5), what are the coordinates of B?
Elenna [48]

<u>ANSWER:</u>

The midpoint of AB is M(-5,1). The coordinates of B are (-6, 7)

<u>SOLUTION: </u>

Given, the midpoint of AB is M(-5,1).  

The coordinates of A are (-4,-5),  

We need to find the coordinates of B.

We know that, mid-point formula for two points A(x_{1}, y_{1}) and B (x_{1}, y_{2}) is given by

M\left(x_{3}, y_{3}\right)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Here, in our problem, \mathrm{x}_{3}=-5, \mathrm{y}_{3}=1, \mathrm{x}_{1}=-4 \text { and } \mathrm{y}_{1}=-5

Now, on substituting values in midpoint formula, we get

(-5,1)=\left(\frac{-4+x_{2}}{2}, \frac{-5+y_{2}}{2}\right)

On comparing, with the formula,

\frac{-4+x_{2}}{2}=-5 \text { and } \frac{-5+y_{2}}{2}=1

-4+\mathrm{x}_{2}=-10 \text { and }-5+\mathrm{y}_{2}=2

\mathrm{x}_{2}=-6 \text { and } \mathrm{y}_{2}=7

Hence, the coordinates of b are (-6, 7).

5 0
4 years ago
Which radical would fall between 13 and 14?
Mice21 [21]

It would be sqrt 175

5 0
3 years ago
What number must you add to complete the square? x^2+26x=33
katrin2010 [14]

Answer:

Must add: 202

Step-by-step explanation:

The \ formula \ for \ perfect \ square => (a + b)^2  = a^2 + 2ab + b^2

a = x

2ab = 26x

2ab = 26a  [ substitute a instead of x]

b = \frac{26a}{2a}

b= 13

So,

  (x + 13)^2 = x^2 + 26x + 169

But given equation is :

       x^2 + 26x = 33\  =>  \ x^2 + 26x -33 = 0

We have find the difference between 169 and -33 to get the number that should be added to get the perfect square.

That is , 169 - (-33) = 202

Therefore ,

   x^2 + 26x -33 + 202 \ makes \ given \ equation  \ a \ perfect \ square

8 0
3 years ago
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