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3 years ago

8

2/7 × (-7/9) in decimal form

2 answers:

Ipatiy [6.2K]3 years ago

3 0

Answer: $-\frac{2}{9}\quad \left(\mathrm{Decimal:\quad }\:-0.22222\dots \right)$

Step-by-step explanation:

$\frac{2}{7}\left(-\frac{7}{9}\right)$

$=-\frac{2}{7}\cdot \frac{7}{9}$

$=-\frac{2}{9}$

$= -0.22222\dots$

krok68 [10]3 years ago

3 0

2.78 2x9=18. 18+7=25. 25➗9=2.777

Therefore it’s 2.78

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5x(f-32)divided by 9 for f = 95

miss Akunina [59]

Answer:

35x

Step-by-step explanation:

$5x(f - 32) \div 9 \\ = \frac{5x(f - 32)}{9} \\ = \frac{5x(95 - 32)}{9} \\ = \frac{5x \times 63}{9} \\ = 5x \times 7 \\ = 35x$

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4 years ago

Select the correct answer.

emmasim [6.3K]

Answer:

the answer is 45/8 very direct

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3 years ago

Read 2 more answers

Find the length of the height of the right trapezoid shown below, if it has the greatest possible area and its perimeter is equa

Artyom0805 [142]

Answer:

The height of the right trapezoid is $\frac{6}{5+\sqrt{3}}\ units$

Step-by-step explanation:

Let

x ----> the height of the right trapezoid in units

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+DH+HA$

we have

$P=6\ units$

$AB=BC=CH=HA=x$ ---> because is a square

substitute

$6=x+x+CD+DH+x$

$6=3x+CD+DH$ -----> equation A

<em>In the right triangle CDH</em>

$sin(30\°)=\frac{CH}{CD}$

$sin(30\°)=\frac{1}{2}$

so

Remember that $CH=x$

$\frac{1}{2}=\frac{x}{CD}$

$CD=2x$

$tan(30\°)=\frac{CH}{DH}$

$tan(30\°)=\frac{\sqrt{3}}{3}$

so

$\frac{\sqrt{3}}{3}=\frac{x}{DH}$

$DH=x\sqrt{3}$

substitute the values in the equation A

$6=3x+CD+DH$ -----> equation A

$CD=2x$

$DH=x\sqrt{3}$

$6=3x+2x+x\sqrt{3}$

$6=5x+x\sqrt{3}$

$6=x[5+\sqrt{3}]$

$x=\frac{6}{5+\sqrt{3}}\ units$

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3 years ago

Jordan and Dajia are both completing homework on Deltamath. Jordan started yesterday and completed three problems and is solving

Sedaia [141]

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3 years ago

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 447 gram setting. It is

lord [1]

Answer:

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 447 gram setting.

$H_0:\mu = 447\\H_a:\mu\neq 447$

Mean = $\mu = 447\\s = 21\\x = 443$

n = 19

Since n < 30 , so we will use t test

$t=\frac{x-\mu}{\frac{s}{\sqrt{n}}}$

Substitute the values :

$t=\frac{443-447}{\frac{21}{\sqrt{19}}}$

$t=−0.8302$

t calculated = -0.830

degree of freedom = n-1 = 19-1 = 18

A level of significance=α=0.025

$t_{(df,\frac{\alpha}{2})}=2.093$

t critical = 2.093

t calculated < t critical

So, We failed to reject null hypothesis

Decision rule -0.830< 2.093 So, We failed to reject null hypothesis

4 0

3 years ago