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zvonat [6]
3 years ago
11

Describe how you would identify mutations that are dominant. Describe how you would identify mutations that are dominant. To ide

ntify dominant mutations, breed the mutant individual to a mutant individual. Dominant mutations will be visible in the F1 generation. To identify dominant mutations, breed the wild-type individual to a wild-type individual. Dominant mutations will be visible in the F1 generation. To identify dominant mutations, breed the mutant individual to a mutant individual. Dominant mutations will be visible in the F2 generation. To identify dominant mutations, breed the mutant individual to a wild-type individual. Dominant mutations will be visible in the F2 generation. To identify dominant mutations, breed the mutant individual to a wild-type individual. Dominant mutations will be visible in the F1 generation.
Biology
1 answer:
maw [93]3 years ago
4 0

Answer:

To identify dominant mutations, breed the mutant individual to a wild-type individual. Dominant mutations will be visible in the F1 generation.

Explanation:

Due to technical problems, you will find the complete explanation in the attached files

Download pdf
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Arrange the sentences in order to describe how oxygen from air is transported to the cells in the kidneys.
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3 years ago
4. The Rh blood type response system is controlled by the D allele. The genotypes DD and Dd are Rh (Rh positive); dd is Rh- (Rh
DedPeter [7]

Answer:

A - Frequency of D allele = 0.35

Frequency of d allele = 0.65

B- Frequency of DD genotype = 0.1225

Frequency of Dd genotype = 0.455

Frequency of dd genotype = 0.425.

C - Total population = 400

Frequency of heterozygous population = 400*0.455 = 183.

EXPLANATION:

The equilibrium sum of all the allelic frequency of a gene is always 1 and sum of all the genotypic frequency of all the genotype is always 1 - This is according to Hardy-Weinberg.

So p+q =1

p2+ 2pq+q2 =1

where p = frequency of dominant allele

q is the frequency of the recessive allele.

from the question, it was given that there were  170 individual out of 400, which were Rh- negative,

So q2 = 170/400 = 0.425

q= 0.65

Also p+q =1

so p = 1-q

or p = 1-0.65

Hence p =0.35

Frequency of homozgupus for D allele = 0.35*0.35 = 0.1225

Frequency of heterozygous or Dd will be 2pq.

or 2*0.35*0.65 = 0.455

A - Frequency of D allele = 0.35

Frequency of d allele = 0.65

B- Frequency of DD genotype = 0.1225

Frequency of Dd genotype = 0.455

Frequency of dd genotype = 0.425.

C - Total population = 400

Frequency of heterozygous population = 400*0.455 = 183.

8 0
3 years ago
Read 2 more answers
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