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diamong [38]
3 years ago
12

Choose the correct symbol to compare these numbers. 0.480 [?] 4.8

Mathematics
1 answer:
Sidana [21]3 years ago
6 0

Answer:    >

Step-by-step explanation:

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Find the surface of the prism
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Answer:

no se podrías resolverlo tu

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Discuss two other ways in which you encounter percentages in a typical week of your life
djverab [1.8K]
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What the answer to this
Blababa [14]
I am pretty sure the answer is A because the graph is a cubic function
5 0
3 years ago
Write an equation in slope-intercept form for each line described passes through (−2, −6) and (4, 6)
pogonyaev

Answer:

y=2x=5

Step-by-step explanation:

the slope of the equation is 2 and the y intercept can be anywhere between -6 and 6 so i just chose 5

5 0
3 years ago
Find the extreme values of the function f(x, y) = 4x2 + 6y2 on the circle x2 + y2 = 1.
julia-pushkina [17]

Answer with Step-by-step explanation:

We are given that

f(x,y)=4x^2+6y^2

Let g(x,y)=x^2+y^2=1

We have to find the extreme values  of the given function

\nabla f(x,y)

\nabla g(x,y)=

Using Lagrange multipliers

\nabla f(x,y)=\lambda \nabla g(x,y)

f_x=\lambda g_x

8x=\lambda 2x

Possible value x=0 or \lambda=4

If x=0 then substitute the value in g(x,y)

Then, we get y=\pm 1

f_y=\lambda g_y

12y=\lambda 2y

If \lambda=4 and substitute in the equation

Then , we  get possible value of y=0

When y=0 substitute in g(x,y) then we get

x=\pm 1

Hence, function has possible  extreme values at points (0,1),(0,-1), (1,0) and (-1,0).

f(0,1)=6

f(0,-1)=6

f(1,0)=4

f(-1,0)=4

Therefore, the maximum value of f  on the circlex^2+y^2=1  is f(0,\pm1)=6 and minimum value of f(\pm1,0)=4

7 0
3 years ago
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