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kobusy [5.1K]
3 years ago
5

What is the simplest form of 3/27a2b7?

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
8 0

Answer:

3ab^2(3/b)

THE ANSWER <u>A</u>

Step-by-step explanation:

2020 HEHE

krok68 [10]3 years ago
4 0

Answer:

the solution is A

Step-by-step explanation:

\sqrt[3]{27a^{3}b^{7}  } \\

\sqrt[3]{(3)^3(a^3)(b^6)b}\\\\3ab^2\sqrt[3]{b}

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4 0
3 years ago
Let sin A= -3/5 with 270°&lt; A&lt; 360°. Find the following.<br> sin A/2
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Answer:

1/sqrt10

Step-by-step explanation:

1) Find out cosA using formula (cosA)^2+(sinA)^2=1

The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5

So cosA=-4/5 or cosA=4/5.

Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.

2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.

(sinA/2)^2= 0.1

sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10

But 270°< A< 360°, then 270/2°<A/2<360/2°

135°<A/2<180°, so sinA/2 must be positive and the only correct answer is

sin A/2= 1/sqrt10

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