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Pachacha [2.7K]
3 years ago
9

What is the value of 6x - 3y if x = 5 and y = -1?

Mathematics
2 answers:
Sergio [31]3 years ago
7 0

Answer:

G. 33

Step-by-step explanation:

6x - 3y \\ 6(5) - 3( - 1) \\ 30 + 3 \\  33

Arisa [49]3 years ago
3 0

<h2>6x-3y</h2>

Now, if x = 5 and y = -1

6(5) -3(-1)

= 30+3

= 33

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Distribute 5 (m+6) please and thank you
antiseptic1488 [7]

Step-by-step explanation:

5 (m+6)

= 5m+5×6

=5m+30

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3 years ago
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Tomika heard that the diagonals of a rhombus are perpendicular to each other. Help her test her conjecture. Graph quadrilateral
Stella [2.4K]

Answer:

a. The four sides of the quadrilateral ABCD are equal, therefore, ABCD is a rhombus

b. The equation of the diagonal line AC is y = 5 - x

The equation of the diagonal line BD is y = 5 - x

c. The diagonal lines AC and BD of the quadrilateral ABCD are perpendicular to each other

Step-by-step explanation:

The vertices of the given quadrilateral are;

A(1, 4), B(6, 6), C(4, 1) and D(-1, -1)

a. The length, l, of the sides of the given quadrilateral are given as follows;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

The length of side AB, with A = (1, 4) and B = (6, 6) gives;

l_{AB} = \sqrt{\left (6-4  \right )^{2}+\left (6-1  \right )^{2}} = \sqrt{29}

The length of side BC, with B = (6, 6) and C = (4, 1) gives;

l_{BC} = \sqrt{\left (1-6  \right )^{2}+\left (4-6  \right )^{2}} = \sqrt{29}

The length of side CD, with C = (4, 1) and D = (-1, -1) gives;

l_{CD} = \sqrt{\left (-1-1  \right )^{2}+\left (-1-4  \right )^{2}} = \sqrt{29}

The length of side DA, with D = (-1, -1) and A = (1,4)   gives;

l_{DA} = \sqrt{\left (4-(-1)  \right )^{2}+\left (1-(-1)  \right )^{2}} = \sqrt{29}

Therefore, each of the lengths of the sides of the quadrilateral ABCD are equal to √(29), and the quadrilateral ABCD is a rhombus

b. The diagonals are AC and BD

The slope, m, of AC is given by the formula for the slope of a straight line as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

Therefore;

Slope, \, m_{AC} =\dfrac{1-4}{4-1} = -1

The equation of the diagonal AC in point and slope form is given as follows;

y - 4 = -1×(x - 1)

y = -x + 1 + 4

The equation of the diagonal AC is y = 5 - x

Slope, \, m_{BD} =\dfrac{-1-6}{-1-6} = 1

The equation of the diagonal BD in point and slope form is given as follows;

y - 6 = 1×(x - 6)

y = x - 6 + 6 = x

The equation of the diagonal BD is y = x

c. Comparing the lines AC and BD with equations, y = 5 - x and y = x, which are straight line equations of the form y = m·x + c, where m = the slope and c = the x intercept, we have;

The slope m for the diagonal AC = -1 and the slope m for the diagonal BD = 1, therefore, the slopes are opposite signs

The point of intersection of the two diagonals is given as follows;

5 - x = x

∴ x = 5/2 = 2.5

y = x = 2.5

The lines intersect at (2.5, 2.5), given that the slopes, m₁ = -1 and m₂ = 1 of the diagonals lines satisfy the condition for perpendicular lines m₁ = -1/m₂, therefore, the diagonals are perpendicular.

5 0
3 years ago
ANSWER PLEASE! WILL MARK BRAINLIEST! OFFERING 30 POINTS!
SSSSS [86.1K]

Answer:

C

Step-by-step explanation:

Work backwards. You are given -3 , -30 for C. If you add -3 + 3 and the divide it by 2 , you get 0. If you add 8 + -20 and divide by 2 you get -6 , so the answer is C.

7 0
3 years ago
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Factor this polynomial completely x2 + 3x – 18 A. (x-2)(x + 9) B. (x+3)(x-6) оо C. (x - 3)(x+6) D. (x - 3)(x-6)​
Umnica [9.8K]

Answer:

C. (x-3)(x+6)

Step-by-step explanation:

I think the equation meant x^2+3x-18?

Anyways, to factor these kinds of quadratic, keep into consideration:

ax^2+bx+c=(x+w)(x+v)

ONLY if:

w+v=b\\wv=c

Start off by finding factors of c, which in this case, -18:

±(1, 2, 3, 6, 9, 18)

If one of the numbers is negative then the other number must be positive.

Find which two factors will sum up to b, which in this case, is 3.

1+(-18)\neq 3\\2+(-9)\neq 3\\3+(-6)\neq 3\\6+(-3)=3\\9+(-2)\neq 3\\18+(-1)\neq 3\\

The only two factors that work are 6 and -3.

Replace them into the factored form:

(x+w)(x+v)\\(x+6)(x-3)\\(x-3)(x+6)

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2 years ago
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what types of correlation would be expected between distance run and calories burned? would this relationship be casual - positi
Jet001 [13]

Answer:

positive correlation, causal

negative correlation, not causal

negative correlation, causal

Step-by-step explanation:

6 0
3 years ago
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