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3 years ago

What is the value of 6x - 3y if x = 5 and y = -1?

Mathematics

2 answers:

Sergio [31]3 years ago

7 0

Answer:

G. 33

Step-by-step explanation:

$6x - 3y \\ 6(5) - 3( - 1) \\ 30 + 3 \\ 33$

Arisa [49]3 years ago

3 0

Now, if x = 5 and y = -1

6(5) -3(-1)

= 30+3

= 33

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In which set do all of the values make the inequality 2x-1<10 true ? A)10-15-20. B)5-7-9 C)4-6-8. D)2-3-4

melamori03 [73]

D is true
$2x - 1 < 10 \\ 2 \times (2) - 1 = 3 \\ 2 \times (3) - 1 = 5 \\ 2 \times (4) - 1 = 7$

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3 years ago

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adell [148]

9514 1404 393

Answer:

A, C, D

Step-by-step explanation:

All three triangles can be proved congruent, so corresponding angles are congruent.

∆JKL ≅ ∆MNO ≅ ∆PQR

So, the statements that are true are ...

A) rigid motion can map ∆JKL to ∆MNO

C) ∆JKL can be proved congruent to ∆PQR

D) ∠N can be proved congruent to ∠Q

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About the other choices

B. When triangles are congruent, there is some rigid motion that maps one to the other. It is false to say there is none such.

E. ∠L has a measure of 65° (not 55°), as do the corresponding angles in the other triangles.

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3 years ago

ABCD- parallelogram, If the perimeter of Triangle CPQ is 15cm, Find the perimeter of triangle BAQ. Find the perimeter of triangl

melamori03 [73]

Answer:

The answer is below

Step-by-step explanation:

A parallelogram is a quadrilateral (has 4 sides and 4 angle) with two pair of parallel and opposite sides. Opposite sides of a parallelogram are parallel and equal.

Given parallelogram ABCD:

AB = CD = 18 cm; BC = AD = 8 cm

∠P = ∠P, ∠PDA = ∠PCQ (corresponding angles are equal).

Hence ΔPCQ and ΔPDA are similar by angle-angle similarity theorem. For similar triangles, the ratio of their corresponding sides equal. Therefore:

$\frac{CD}{PC}= \frac{AD}{CQ}\\\\\frac{18}{6}=\frac{8}{x} \\\\x=\frac{6*8}{18}=\frac{8}{3}\ cm$

Perimeter of CPQ = CP + CQ + PQ

15 = 6 + 8/3 + PQ

PQ = 15 - (6 + 8/3)

PQ = 6.33

∠CQP = ∠AQB (vertical angles), ∠QCP = ∠QBA (alternate angles are equal).

Hence ΔCPQ and ΔABQ are similar by angle-angle similarity theorem

$\frac{AQ}{QP}=\frac{AB}{CP} \\\\\frac{AQ}{6.33} =\frac{18}{6} \\\\AQ=\frac{18}{6}*6.33\\\\AQ = 19$

$\frac{BQ}{CQ}=\frac{AB}{CP} \\\\\frac{BQ}{8/3} =\frac{18}{6} \\\\BQ=\frac{18}{6}*\frac{8}{3} \\\\BQ =8$

Perimeter of BAQ = AB + BQ + AQ = 18 + 8 + 19 = 45cm

PA = AQ + PQ = 19 + 6.33 = 25.33

PD = CD + DP = 18 + 6 = 24

Perimeter of PDA = PA + PD + AD = 24 + 25.33 + 8 = 57.33 cm

7 0

3 years ago

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kiruha [24]

Answer:

<h2>Option B:</h2><h2> $\frac{1}{5}$ </h2>

Step-by-step explanation:

Given,

Number of numbers of each side of the cube

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= 6 numbers

Number of sides of cube having the number 5

= 1

Therefore, 

Probability of getting a side of the cube of no. 5 is

$= \frac{no. \: of \: favourable \: outcomes}{total \: no. \: of \: possible \: outcomes}$

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anzhelika [568]

4.94*10^13 / 2.6*10^10=1.9 * 10^3=1900 times

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3 years ago