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AysviL [449]
4 years ago
14

Four different sets of objects contain 4, 5, 6, and 8 objects, respectively. How many unique combinations can be formed by picki

ng one object from each set?
Mathematics
2 answers:
ser-zykov [4K]4 years ago
8 0

You would multiply all of the numbers to get your answer so it would be 4*5*6*8 which would get you 960.

Charra [1.4K]4 years ago
4 0

Answer: 960

Step-by-step explanation:

Given: Four different sets of objects contain 4, 5, 6, and 8 objects, respectively.

The number of unique combinations formed by picking one object from each set is given by :-

\text{Total unique combinations}=4\times5\times6\times8\\\\\Rightarrow\text{Total unique combinations}=960

Hence, the number of unique combinations formed by picking one object from each set is 960.

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10 points
aivan3 [116]

Answer:

20.18

Step-by-step explanation:

Greatest number= 35.18

Least number=15

Difference between the twain=20.18

5 0
3 years ago
Read 2 more answers
Find the values for a and b that would make the equality true.
Crank

Answer:

a = - 4, b = 5

Step-by-step explanation:

Expand the left side and compare the coefficients of like terms on the right side.

- 3(2x² + ax + b)

= - 6x² - 3ax - 3b

Comparing like terms with - 6x² + 12x - 15

x - term → - 3a = 12 ( divide both sides by - 3 )

                    a = - 4

constant term → - 3b = - 15 ( divide both sides by - 3 )

                               b = 5

6 0
3 years ago
What number is greater 87 or 13.688?
Alex_Xolod [135]
87 is greater of course
6 0
3 years ago
Read 2 more answers
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natali 33 [55]

Answer:

I think. its below

Step-by-step explanation:

1 x 8 = 8

4 x 8 = 32

4 0
3 years ago
Ameeta finished 12 math problems. David finished 3 times as many. How many more math problems did David finish than Ameeta?
Volgvan
  • Answer:
  • david finished 24 problems more than ameetha
  • Step-by-step explanation:
  • <em>problems finished by ameetha = 12 problems</em>
  • <em>problems finished by ameetha = 12 problemsproblems finished by David = 3 times more than ameethas problem = 3*12 = 36</em>
  • <em>problems finished by ameetha = 12 problemsproblems finished by David = 3 times more than ameethas problem = 3*12 = 36the problems finished by David more than ameetha =</em>
  • <em>problems finished by ameetha = 12 problemsproblems finished by David = 3 times more than ameethas problem = 3*12 = 36the problems finished by David more than ameetha =36-12= 24 </em>
  • <em>problems finished by ameetha = 12 problemsproblems finished by David = 3 times more than ameethas problem = 3*12 = 36the problems finished by David more than ameetha =36-12= 24 so David finished 24 problems more than ameetha</em>
8 0
4 years ago
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