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valentina_108 [34]
3 years ago
7

Y=x+10 30x+20y=1000What is the solution to the system?

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
6 0

Answer:

x= 99 over 5

Step-by-step explanation:

Go and ask ur teacher

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In a triangle ABC two points D,E are taken on BC so that angle BAD=angle DAE=angleCAE. Determine AE if AB=5,BC=10 angle BAC=90.
lord [1]

Answer:

AE = 7.5

Step-by-step explanation:

Since <BAC = 90^{0}, then;

<BAD = <DAE = <CAE = 30^{0} (complementary angles)

From ΔABC, applying the Pythagoras theorem to determine the length of side AC;

/BC/^{2} = /AC/^{2} + /AB/^{2}

/10/^{2} = /AC/^{2} + /5/^{2}

100 = /AC/^{2} + 25

/AC/^{2} = 100 - 25

/AC/^{2} = 75

AC = \sqrt{75}

Applying trigonometric function to ΔCAE,

Cos 30^{0} = \frac{AE}{\sqrt{75} }

AE = \sqrt{75} × Cos 30^{0}

    = 7.5

Therefore, AE = 7.5

4 0
3 years ago
What is the slope of the line?<br><br> y = -5x - 9<br><br> Slope =<br><br> Help Please
Maksim231197 [3]
The slope is the same as the gradient

y=mx+c where m is the gradient and c is the y intercept
y=-5x-9

Therefore the 'slope' is -5 i.e. it goes down 5 every 1 across.
5 0
3 years ago
Show all work to identify the asymptotes and state the end behavior of the function f(x)=4x/x-16
sergij07 [2.7K]

Answer:

asymptotes: x = 16   zeros: x = 0

The vertical asymptotes of the rational expression are the places where the denominator is zero:

 x -16 = 0 . . . . . true for x=16

__

The zeros of a rational expression are the places where the numerator is zero:

 4x = 0

 x = 0 . . . . . . divide by 4

asymptotes: x = 16   zeros: x = 0

learn more about asymptotes and zeros here:

brainly.com/question/16908830

#SPJ1

8 0
2 years ago
10 red cards and 10 and black cards are placed in a bag. You choose one card and then another without replacing the first card.
MrMuchimi
2/10 right ? hope this helped :)
4 0
3 years ago
John needs 20 grams of 54% acid solution for his science project. His school's science lab has bottles of 30% solution and bottl
Paul [167]

Answer:

John should use:

4 grams of the 30% solution and 16 grams of the 60% solution

Step-by-step explanation:

Let the number of grams of the 30% solution = x

Let the number of grams of the 60% solution = y

John needs 20 grams of 54% acid solution for his science project.

Hence,

x + y = 20 grams..... Equation 1

x = 20 - y

His school's science lab has bottles of 30% solution and bottles of 60% solution.

30% × x + 60% × y = 54% × 20

0.3x + 0.6y = 10.8......Equation 2

We substitute 20 - y for x in Equation 2

0.3(20 - y) + 0.6y = 10.8

6 - 0.3y + 0.6y = 10.8

- 0.3y + 0.6y = 10.8 - 6

0.3y = 4.8

y = 4.8/3

y = 16 grams

x = 20 - y

x = 20 - 16

x = 4 grams

Therefore, John should use:

4 grams of the 30% solution and 16 grams of the 60% solution

7 0
3 years ago
Read 2 more answers
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