Answer:
Problem:
Solve 3x−y=6;y=x−4
Steps:
I will try to solve your system of equations.
y=x−4;3x−y=6
Step: Solvey=x−4for y:
Step: Substitutex−4foryin3x−y=6:
3x−y=6
3x−(x−4)=6
2x+4=6(Simplify both sides of the equation)
2x+4+−4=6+−4(Add -4 to both sides)
2x=2
2x
2
=
2
2
(Divide both sides by 2)
x=1
Step: Substitute1forxiny=x−4:
y=x−4
y=1−4
y=−3(Simplify both sides of the equation)
Answer:
y=−3 and x=1
Step-by-step explanation:
Hope this helped you
It’s a question because there is not value of time.
The angles of a quadrilateral add to 360, so we can solve for x by adding the 4 angle measures together and setting it equal to 360:
90 + 140 + (x - 10) + (x - 20) = 360
Combine like terms:
230 + 2x - 30 = 360
200 + 2x = 360
200 - (200) + 2x = 360 - (200)
2x = 160
Divide both sides by 2:
2x/(2) = 160/(2)
x = 80
Given
2x³ + (x³ - 3) sin(2πy) - 3y = 0
we first notice that when x = ³√3, we get
2 (³√3)³ + ((³√3)³ - 3) sin(2πy) - 3y = 0
2•3 + (3 - 3) sin(2πy) - 3y = 0
6 - 3y = 0
3y = 6
y = 2
Differentiating both sides with respect to x gives
6x² + 3x³ sin(2πy) + 2π (x³ - 3) cos(2πy) y' - 3y' = 0
Then when x = ³√3, we find
6(³√3)² + 3(³√3)³ sin(2π•2) + 2π ((³√3)³ - 3) cos(2π•2) y' - 3y' = 0
6•³√9 + 3•3 sin(4π) + 2π (3- 3) cos(4π) y' - 3y' = 0
6•³√9 + 0 + 0 - 3y' = 0
3y' = 6•³√9
y' = 2•³√9
(that is, 2 times the cube root of 9)
Answer:
It is 7
Step by step explanation:
5 divided by 2/3 equals 7.5, which means she can bake 7 whole pies.
