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Time taken before they are 2640 feet is 146.67 seconds
<em><u>Solution:</u></em>
The distance is given by formula:
<em><u>Ton travels at 8 feet per second</u></em>
Let us assume, time taken = t
speed = 8 feet per second
Then, distance is given as:
Distance covered by Ton = 8t
<em><u>Bob travels at 10 feet per second</u></em>
Then, distance is given as:
Distance covered by Bob = 10t
How long will it take before they are 2640 feet
Which means,
Distance covered by Ton + Distance covered by Bob = 2640
Thus time taken before they are 2640 feet is 146.67 seconds
<h3><u>Method 2:</u></h3>Since trains are moving in opposite directions, their speeds must be added
speed = 8 + 10 = 18 feet per second
Given distance = 2640 feet
Therefore, time taken is:
Thus time taken before they are 2640 feet is 146.67 seconds
Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.
Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)