The answer is C.
All of the other answers are incorrect
End behavior: f. As x -> 2, f(x) -> ∞; As x -> ∞, f(x) -> -∞
x-intercept: a. (3, 0)
Range: p. (-∞, ∞)
The range is the set of all possible y-values
Asymptote: x = 2
Transformation: l. right 2
with respect to the next parent function:

Domain: g. x > 2
The domain is the set of all possible x-values
Answer:
x+ y = 75
Step-by-step explanation:
The both paid a total of 75.
Therefore, in order to get 75 you would need to add the amount each of them paid.
Answer:
Step-by-step explanation:
6x+9=63
6x=63-9
6x=54
x=54/6
x=9
I encourage you to figure out the justification yourself.
Answer:
The answer is "Options A, B, and E represent mutually exclusive events".
Step-by-step explanation:
Two occurrences that can happen immediately called mutually incompatible. Let's now glance at our options and figure out where the statements are mutually incompatible events.
In Option A: You could see that landing on an unwanted portion and arriving on 2 are events that are locally incompatible, even as undesirable portion contains 3 and 4, and 2 were shaded.
In Option B: Arriving on a shaded part and falling on 3 are also mutually incompatible because there are 3 on a windows azure.
In Option C: A darkened portion and an increasing amount can land while 2 would be an even number as well as on the shaded portion. That number is very much the same.
In Option D: At the same time as 4 is greater than 3 and it is situated upon an undistressed section, landing and attracting a number larger than 3 can happen.
In Option E: Landing on a shaded part and landing on even a shaded part is an excluding event, since shaders may either be shaded or unlit.