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Mazyrski [523]
3 years ago
7

Plz help. due tomorrow!

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
3 0
What idk jk sorry trying to be funny like always but what is the question I have no picture
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Dan bought 6 new baseball trading cards to add to his collection. The next day, his dog ate half of his collection. There are no
Vika [28.1K]

Answer:

50 cards

Step-by-step explanation:

28*2= 56

56-6=50

3 0
3 years ago
Read 2 more answers
I will give you branilest! <br> Solve 1/3(x-10)= -4
Olegator [25]

Answer:

x = -2

Step-by-step explanation:

Multiply both sides by 3 to get rid of the fraction:

x - 10 = -12

Add 10 to both sides:

x = -2

3 0
3 years ago
There are 527 pencils,646 erasers and 748 sharpeners. These are to be put in separate packets containing the same number of item
sp2606 [1]

Answer:

  • 31 pencils
  • 38 erasers
  • 44 sharpeners

Step-by-step explanation:

The number of packets is the greatest common divisor of the given numbers of pencils, erasers, and sharpeners.

It can be helpful to look at the differences between these numbers:

  748 -646 = 102

  646 -527 = 119

The difference of these differences is 17, suggesting that will be the number of packets possible.

  527 = 17 × 31

  646 = 17 × 38

  748 = 17 × 44

The numbers 31, 38, and 44 are relatively prime (31 is actually prime), so there can be no greater number of packets than 17.

There will be 31 pencils, 38 erasers, and 44 sharpeners in each of the 17 packets.

_____

We may have worked the wrong problem. The way it is worded, the <em>maximum</em> number of items in each packet will be 527 pencils, 646 erasers, and 748 sharpeners in one (1) packet. The <em>minimum</em> number of items in each packet will be the number that corresponds to the maximum number of packets. Since 17 is the maximum number of packets, each packet's contents are as described above.

17 is the only common factor of the given numbers, so will be the number of groups (plural) into which the items can be arranged.

6 0
3 years ago
Which equation is equivalent to 16 Superscript 2 p Baseline = 32 Superscript p 3?.
Mrac [35]

The equation which is equivalent to 16 Superscript 2 p Baseline equal to 32 Superscript p 3 is,

2^{8p}=2^{5p+15}

<h3>What is equivalent equation?</h3>

Equivalent equation are the expression whose result is equal to the original expression, but the way of representation is different.

Given information-

The given equation in the problem is,

16^{2p}=32^{p+3}

Write both the equation in the form of same base number as,

(2^4)^{2p}=(2^5)^{p+3}

The power of the power of a number can be written as product of both the numbers. Thus,

(2)^{4\times2p}=(2)^{5\times(p+3)}\\2^{8P}=2^{5P+15}

This is the required equation.

Now if the base is the same at both side of the expression, then the powers can be compared. Thus,

8p=5p+15

Solve it further to find the value of p as,

8p-5p=15\\3p=15\\p=5

Thus the equation which is equivalent to 16 Superscript 2 p Baseline equal to 32 Superscript p 3 is,

2^{8p}=2^{5p+15}

Learn more about the equivalent expression here;

brainly.com/question/2972832

7 0
2 years ago
If A⊥Y and X || Y, then _____
Mariana [72]

Answer:

A⊥X

Step-by-step explanation:

Since

A is perpendicular to Y

A⊥Y

And, X is parallel to Y

X || Y

Which means that they have the same slope (same inclination)

That implies that A must be also perpendicular to X

A⊥X

4 0
3 years ago
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