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3 years ago

The graph below has the same shape. What is the equation of the blue graph????????

Mathematics

1 answer:

vesna_86 [32]3 years ago

4 0

Answer: The answer is a ahahahha thats funny im in 8th grade and i figured that out and we are not even doing that yet its just infering

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What is the distance between the points (-12, 11) and (-18, 17), to the<br> nearest tenth? *

Basile [38]

Answer:

8.5 units

Step-by-step explanation:

The distance between two points is given by

$d=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Taking points (-12, 11) and (-18, 17) as the first and second points respectively then

$d=\sqrt{(-18--12)^{2}+(17-11)^{2}}$

$d=\sqrt {36+36}$

d=8.48528137423857 units

Rounded off to nearest tenths

d=8.5 units

6 0

3 years ago

A helicopter hovers 500 feet above a small island. The figure shows that the angle of

Tamiku [17]

Answer:

435 ft

Step-by-step explanation:

Reference angle = <P = 49° (angle of elevation)

Opposite side = 500 ft

Adjacent side = d = ?

Apply trigonometric function, TOA.

This:

Tan P = opp/adj

Tan 49 = 500/d

d × Tan 49 = 500

d = 500/Tan 49

d = 434.643369 ≈ 435 ft (to the nearest foot)

6 0

3 years ago

Show work please help

Snezhnost [94]

Answer:

20 yd^2

Step-by-step explanation:

Your work is partially correct.

Assuming that the sides marked 8 yds and 2 yds are parallel, then the area of the trapezoid is

A = ( 8 yds + 2 yds)

------------------------ * 4 = 20 yd^2

4 0

3 years ago

A food packet is dropped from a helicopter and is modeled by the function f(x) = −15x2 + 6000. The graph below shows the height

melisa1 [442]

General Idea:

Domain of a function means the values of x which will give a DEFINED output for the function.

Applying the concept:

Given that the x represent the time in seconds, f(x) represent the height of food packet.

Time cannot be a negative value, so

$x\geq 0$

The height of the food packet cannot be a negative value, so

$f(x)\geq 0$

We need to replace $-15x^2+6000$ for f(x) in the above inequality to find the domain.

$-15x^2+6000\geq 0 \; \; [Divide \; by\; -15\; on\; both\; sides]\\ \\ \frac{-15x^2}{-15} +\frac{6000}{-15} \leq \frac{0}{-15} \\ \\ x^2-400\leq 0\;[Factoring\;on\;left\;side]\\ \\ (x+200)(x-200)\leq 0$

The possible solutions of the above inequality are given by the intervals $(-\infty , -2], [-2,2], [2,\infty )$ . We need to pick test point from each possible solution interval and check whether that test point make the inequality $(x+200)(x-200)\leq 0$ true. Only the test point from the solution interval [-200, 200] make the inequality true.