Question

5

Answer 1

Answer:

Answer is B edg2021

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Answer 2

Answer:

$\sum\limits^5_{n=1} {2^{n-2}} = 15.5$

Step-by-step explanation:

Given

$\sum\limits^5_{n=1} {2^{n-2}$

Required

The result

To do this, we simply substitute 1 to 5 for n.

So, we have:

$\sum\limits^5_{n=1} {2^{n-2}} = 2^{1-2} + 2^{2-2} + 2^{3-2} + 2^{4-2} + 2^{5-2}$

$\sum\limits^5_{n=1} {2^{n-2}} = 2^{-1} + 2^{0} + 2^{1} + 2^{2} + 2^{3}$

Evaluate each exponent

$\sum\limits^5_{n=1} {2^{n-2}} = 0.5 + 1 + 2 + 4 +8$

$\sum\limits^5_{n=1} {2^{n-2}} = 15.5$