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neonofarm [45]
3 years ago
7

TRUE OR FALSE (i really don't know what the right answer is i was hoping anyone else would know)

Mathematics
2 answers:
vaieri [72.5K]3 years ago
8 0
I think the answer is a
notsponge [240]3 years ago
3 0

I think it's A

Step-by-step explanation:

true

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Pls help DUE TODAY (13points)
Brut [27]

Answer:

42 ft²

Step-by-step explanation:

Rectangle Area: L * W

\bf A=(8ft)(6ft)

\bf 48 \; ft^2

\bf A= (3ft)(2ft)

\bf 6\;ft^2

\bf 48ft^2-6ft^2

\boxed{\bf 42\; ft^2}

8 0
2 years ago
Read 2 more answers
Three cards are chosen from a standard deck of 52 playing cards with replacement what is the orobsbility every card will be a he
Ne4ueva [31]
1/4 x 1/4 x 1/4 = 1/64

There is a 1/64 chance that they will all be hearts.
7 0
3 years ago
elisa owns 28% of the grudman corporations . The rest of the shares are owned equally by the remaining six share holders . what
dolphi86 [110]

OK so there is 72% of the company left to share. Divide that by six you get 12.

Each shareholder has 12% of the company.

7 0
3 years ago
Read 2 more answers
NO LINKS!!! Part 2: Find the Lateral Area, Total Surface Area, and Volume. Round your answer to two decimal places.​
slava [35]

Answer:

<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

The bases of a triangular prism are the triangles.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2

<u>Total Surface Area</u>

Area of the isosceles triangle:

\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2

Total surface area:

\implies \sf T.A.=2\:bases+L.A.=2\left(\dfrac{3\sqrt{391}}{4}\right)+138=167.66\:\:m^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)

<h3><u>Question 8</u></h3>

<u>Lateral Surface Area</u>

The bases of a hexagonal prism are the pentagons.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

\implies \sf L.A.=5(5 \times 6)=150\:\:cm^2

<u>Total Surface Area</u>

Area of a pentagon:

\sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}a^2

where a is the side length.

Therefore:

\implies \sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}\cdot 5^2=43.01\:\:cm^2\:(2\:d.p.)

Total surface area:

\sf \implies T.A.=2\:bases+L.A.=2(43.01)+150=236.02\:\:cm^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=43.011193... \times 6=258.07\:\:cm^3\:(2\:d.p.)

8 0
2 years ago
The area of rectangular is 64m the length of the pool is 12 m less that the width .The situation can be represented by the equat
beks73 [17]

Answer:

Width = 16 m

Length = 4 m

Step-by-step explanation:

The area of rectangular is 64m² the length of the pool is 12 m less that the width . The situation can be represented by the equation x

Area of a rectangle = Length × Width

L = W - 12

Hence:

64 = (W - 12) × W

64 = W² - 12W

W² - 12W - 64 = 0

Factor using

(W + 4)(W - 16) = 0

Width = 16m

Length = W - 12

Length = 16 m - 12 m

= 4 m

6 0
3 years ago
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