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vfiekz [6]
3 years ago
9

I need help !! Which ones have a Proportional relationship?? Need help now !

Mathematics
1 answer:
dexar [7]3 years ago
4 0

Answer:

From what I can see in the picture, the table is a proportional relationship.

y= 2.5x

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solniwko [45]

Answer:

Step-by-step explanation:

the areas are the same, the outer squares of Q are the ones missing in the center

7 0
1 year ago
The odds of winning a game are given as 1:25. what is the probability that you will win this game? what is the probability that
muminat
<span>The probability that I will win this game is 4%
</span>The probability that I will lose this game is 96%
The 1, that is on the left side of the colon, needs to increase in order to increase the probability of winning.
6 0
3 years ago
Multiply and Simplify. 4x+4/x^2 × (x+2)(x-1)/x+1
NARA [144]

Answer:


Step-by-step explanation:

(x^2 - 4)(x^2 - 4)

Simplifying

(x2 + -4)(x2 + -4)

Reorder the terms:

(-4 + x2)(x2 + -4)

Reorder the terms:

(-4 + x2)(-4 + x2)

Multiply (-4 + x2) * (-4 + x2)

(-4(-4 + x2) + x2(-4 + x2))

((-4 * -4 + x2 * -4) + x2(-4 + x2))

((16 + -4x2) + x2(-4 + x2))

(16 + -4x2 + (-4 * x2 + x2 * x2))

(16 + -4x2 + (-4x2 + x4))

Combine like terms: -4x2 + -4x2 = -8x2

(16 + -8x2 + x4)

5 0
3 years ago
Marcus wanted to buy his mom a Christmas present and planned to spend $100. He ending up finding a really great present but actu
dedylja [7]

Answer:

The percent of his error is 20.5%

Step-by-step explanation:

subtract 100 from 120.50 and then divide the answer by 100. Then move the decimal point two places to the right to get 20.5%.

6 0
3 years ago
Read 2 more answers
Tomika heard that the diagonals of a rhombus are perpendicular to each other. Help her test her conjecture. Graph quadrilateral
Stella [2.4K]

Answer:

a. The four sides of the quadrilateral ABCD are equal, therefore, ABCD is a rhombus

b. The equation of the diagonal line AC is y = 5 - x

The equation of the diagonal line BD is y = 5 - x

c. The diagonal lines AC and BD of the quadrilateral ABCD are perpendicular to each other

Step-by-step explanation:

The vertices of the given quadrilateral are;

A(1, 4), B(6, 6), C(4, 1) and D(-1, -1)

a. The length, l, of the sides of the given quadrilateral are given as follows;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

The length of side AB, with A = (1, 4) and B = (6, 6) gives;

l_{AB} = \sqrt{\left (6-4  \right )^{2}+\left (6-1  \right )^{2}} = \sqrt{29}

The length of side BC, with B = (6, 6) and C = (4, 1) gives;

l_{BC} = \sqrt{\left (1-6  \right )^{2}+\left (4-6  \right )^{2}} = \sqrt{29}

The length of side CD, with C = (4, 1) and D = (-1, -1) gives;

l_{CD} = \sqrt{\left (-1-1  \right )^{2}+\left (-1-4  \right )^{2}} = \sqrt{29}

The length of side DA, with D = (-1, -1) and A = (1,4)   gives;

l_{DA} = \sqrt{\left (4-(-1)  \right )^{2}+\left (1-(-1)  \right )^{2}} = \sqrt{29}

Therefore, each of the lengths of the sides of the quadrilateral ABCD are equal to √(29), and the quadrilateral ABCD is a rhombus

b. The diagonals are AC and BD

The slope, m, of AC is given by the formula for the slope of a straight line as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

Therefore;

Slope, \, m_{AC} =\dfrac{1-4}{4-1} = -1

The equation of the diagonal AC in point and slope form is given as follows;

y - 4 = -1×(x - 1)

y = -x + 1 + 4

The equation of the diagonal AC is y = 5 - x

Slope, \, m_{BD} =\dfrac{-1-6}{-1-6} = 1

The equation of the diagonal BD in point and slope form is given as follows;

y - 6 = 1×(x - 6)

y = x - 6 + 6 = x

The equation of the diagonal BD is y = x

c. Comparing the lines AC and BD with equations, y = 5 - x and y = x, which are straight line equations of the form y = m·x + c, where m = the slope and c = the x intercept, we have;

The slope m for the diagonal AC = -1 and the slope m for the diagonal BD = 1, therefore, the slopes are opposite signs

The point of intersection of the two diagonals is given as follows;

5 - x = x

∴ x = 5/2 = 2.5

y = x = 2.5

The lines intersect at (2.5, 2.5), given that the slopes, m₁ = -1 and m₂ = 1 of the diagonals lines satisfy the condition for perpendicular lines m₁ = -1/m₂, therefore, the diagonals are perpendicular.

5 0
3 years ago
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