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borishaifa [10]
3 years ago
14

Plz help...................

Mathematics
2 answers:
marissa [1.9K]3 years ago
8 0
The prime number is 53 because the others have factors other than itself and 1 but 53 doesn't
Aleksandr [31]3 years ago
5 0
53 is a prime

27: 9 x 3, etc
91: 13 x 7, etc
14: 7 x 2, etc

hope this helps


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Please help me ASAP: Answer with : includes / not includes
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Answer:

Step-by-step explanation:

The interval [4, ∞) all real numbers 4 and greater, whereas the interval (4,∞) not includes the endpoint 4.

3 0
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dalvyx [7]

Answer:

38 is the correct solution

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2 years ago
Factor gcf 5ab^2 + 10ab
Mrrafil [7]
<span>5ab^2 + 10ab

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so GCF of </span>5ab^2 + 10ab = 5ab
4 0
3 years ago
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Find the common difference of the sequence shown 1/6,1/3,1/2,2/3,......
tekilochka [14]

Answer:

Common Difference(d) is    

               d=\frac{1}{6}

Step-by-step explanation:

Given sequence is :

                 \frac{1}{6}, \frac{1}{3} ,\frac{1}{2} ,\frac{2}{3} .........

If a sequence has a constant common difference throughout the sequence, then the sequence is called Arithmetic Progression.

Considering a sequence:

       a_1,a_2,a_3,a_4..........\\

a_2-a_1=a_3-a_2=a_4-a_3=a_n-a_n_-_1=d

where 'd' is the common difference of the A.P.

Similarly, finding the common difference of the given sequence.

       

                           \frac{1}{3} -\frac{1}{6}= \frac{1}{2}- \frac{1}{3}=\frac{2}{3} - \frac{1}{2}=d\\

                              d=\frac{1}{3}-\frac{1}{6}=\frac{(2)(1)-(1)(1)}{6}=\frac{1}{6}

                                   d=\frac{1}{6}

Common Difference(d) is    

               d=\frac{1}{6}

8 0
3 years ago
Read 2 more answers
The population of a small town in 1990 was 1,200 people, and the population in 2000 was 2,700 people. Let x represent the number
zheka24 [161]
Well... looking at how to question is defining things.....i think this is a multiple choice question.....

Given:
"y" represents the population
"x" represents the number of years
duration = 2000 - 1990 = 10 years
population increase = 2700 - 1200 = 1500
Now,
<u></u><u>It says linear equation........</u><u>, So, we have to assume that every ten years the population increases by a fixed </u><u>amount that is 1500 people every 10 years.</u><u />

Now, 
Every 10 years, the population increases by 1500
Every 1 year , the population increases by 1500 / 10 
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Now,
The equation in determining the population is:

y = 150x + 1200


<u />
4 0
3 years ago
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