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kenny6666 [7]
3 years ago
14

Write an equation of the line that passes through the given point and is parallel to the given line.

Mathematics
2 answers:
swat323 years ago
8 0

Answer:

Remember that the standard form of a line equation is y = mx + b.   Since you need a line that is parallel to y = 5x - 2, the first thing to do is use the same slope (m), which is 5 in this case.

Step-by-step explanation:

nekit [7.7K]3 years ago
7 0

Remember that the standard form of a line equation is y = mx + b.   Since you need a line that is parallel to y = 5x - 2, the first thing to do is use the same slope (m), which is 5 in this case.

The new line would look like this:  y = 5x + b.  I use "b" instead of -2, since we'll calculate a "b" for the new line by substituting the given point of (2, -1) into y = 5x + b.

 -1 = 5*(2) + b

 b = -11  

The parallel line that goes through (2,-1) is y = 5x - 11

The new line is the blue, on the right.  Note that it is parallel to the original (green) line and also intersects at  (2, -1).  (Each chart is is 0.5 unit).

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