5x-8< -18
+8 on both sides
5x< -10
X< -2
Let: A = adult tickets; S = student tickets
a. 498 = 5A + 3S
118 = A + S
b. S = 118 - A
498 = 5A + 3(118 - A)
498 = 5A + 354 - 3A
498 - 354 = 2A
144 = 2A
A = 72
118 = S + A
118 = 72 + S
118 - 72 = S
S = 46
c. Therefore, there were 72 adult tickets and 46 student tickets sold.
21/49
= (21/7) / (49/7)
= 3/7.
The final answer is 3/7~
