Simplify 32q^9r^4 / 4q^3r
2 answers:
You might be interested in
Answer:
For the average to be above 90, the marks in the fourth paper should be MORE THAN 92.
Step-by-step explanation:
The score of students in last 3 exams = 89 , 87 and 92
Let us assume the marks scored by the student in last exam = k
The average of marks should be above 90.
Now,
Sum of all 4 paper's marks = 89 + 87 + 92 + k = 268 + k
Also, 90 < Average
Hence,for the average to be above 90, the marks in the fourth paper should be MORE THAN 92.