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3 years ago

-6 x -1 x -2 x -3 help me or ur racist to asians

Mathematics

2 answers:

nirvana33 [79]3 years ago

8 0

Answer:

-21

Step-by-step explanation:

Schach [20]3 years ago

6 0

<h2>answer = 36</h2><h2>-------------------------</h2>

<u>Step-by-step explanation:</u>

= -6 x -1 x -2 x -3

= 6 × -2 × -3

= -12 × -3

= 36

<h2>-------------------------</h2><h2>Follow me</h2>

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<img src="https://tex.z-dn.net/?f=4x%2B6%3D11" id="TexFormula1" title="4x+6=11" alt="4x+6=11" align="absmiddle" class="latex-for

nlexa [21]

Answer:

x = $\frac{5}{4}$

Step-by-step explanation:

Given

4x + 6 = 11 ( subtract 6 from both sides )

4x = 5 ( divide both sides by 4 )

x = $\frac{5}{4}$ = 1.25

4 0

3 years ago

Read 2 more answers

If a 4 x 16 rectangle has the same area as a square, what is the length of a side of the square?

Licemer1 [7]

Answer:

Option D. 8 units

Step-by-step explanation:

step 1

Find the area of rectangle

The area of rectangle is

$A=(4)(16)=64\ units^2$

step 2

Find the length side of the square with the same area of rectangle

The area of a square is

$A=b^2$

where

b is the length side of the square

we have

$A=64\ units^2$

substitute

$64=b^2$

take the square root both sides

$b=8\ units$

therefore

The length side of the square is 8 units

7 0

3 years ago

Find two power series solutions of the given differential equation about the ordinary point x = 0. compare the series solutions

monitta

I don't know what method is referred to in "section 4.3", but I'll suppose it's reduction of order and use that to find the exact solution. Take $z=y'$ , so that $z'=y''$ and we're left with the ODE linear in $z$ :

$y''-y'=0\implies z'-z=0\implies z=C_1e^x\implies y=C_1e^x+C_2$

Now suppose $y$ has a power series expansion

$y=\displaystyle\sum_{n\ge0}a_nx^n$
$\implies y'=\displaystyle\sum_{n\ge1}na_nx^{n-1}$
$\implies y''=\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}$

Then the ODE can be written as

$\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge1}na_nx^{n-1}=0$

$\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge2}(n-1)a_{n-1}x^{n-2}=0$

$\displaystyle\sum_{n\ge2}\bigg[n(n-1)a_n-(n-1)a_{n-1}\bigg]x^{n-2}=0$

All the coefficients of the series vanish, and setting $x=0$ in the power series forms for $y$ and $y'$ tell us that $y(0)=a_0$ and $y'(0)=a_1$ , so we get the recurrence

$\begin{cases}a_0=a_0\\\\a_1=a_1\\\\a_n=\dfrac{a_{n-1}}n&\text{for }n\ge2\end{cases}$

We can solve explicitly for $a_n$ quite easily:

$a_n=\dfrac{a_{n-1}}n\implies a_{n-1}=\dfrac{a_{n-2}}{n-1}\implies a_n=\dfrac{a_{n-2}}{n(n-1)}$

and so on. Continuing in this way we end up with

$a_n=\dfrac{a_1}{n!}$

so that the solution to the ODE is

$y(x)=\displaystyle\sum_{n\ge0}\dfrac{a_1}{n!}x^n=a_1+a_1x+\dfrac{a_1}2x^2+\cdots=a_1e^x$

We also require the solution to satisfy $y(0)=a_0$ , which we can do easily by adding and subtracting a constant as needed:

$y(x)=a_0-a_1+a_1+\displaystyle\sum_{n\ge1}\dfrac{a_1}{n!}x^n=\underbrace{a_0-a_1}_{C_2}+\underbrace{a_1}_{C_1}\displaystyle\sum_{n\ge0}\frac{x^n}{n!}$

4 0

3 years ago

What is 5 divided by 5

Triss [41]

Answer:

Step-by-step explanation:

You have 5 jelly beans and 4 imaginary friends

You have to split the jellybeans between yourself and your pretend friends.

Each of you gets 1 jellybean

(Except you get all the jellybeans because your friends don't exist)

Hope this helps :)

6 0

3 years ago

Given An = 5a(n-1) where a1= 2. What are the first 4 terms

nexus9112 [7]

Answer:

2, 10, 50, 250

Step-by-step explanation:

Using the formula with a₁ = 2 , then

a₂ = 5a₁ = 5 × 2 = 10

a₃ = 5a₂ = 5 × 10 = 50

a₄ = 5a₃ = 5 × 50 = 250

The first 4 terms are 2, 10, 50, 250

8 0

3 years ago