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mestny [16]
3 years ago
6

PLEASEEE HURRRY!!!!!!!

Mathematics
2 answers:
lukranit [14]3 years ago
8 0

the answer is D 9.2 units

vichka [17]3 years ago
4 0

Answer:

Option D. 9.2 units.

Step-by-step explanation:

In the ΔJKL ⇒ ∠J + ∠K + ∠L = 180

                      ∠J + 67 + 74 = 180° ⇒ ∠J = 39°

In the given triangle JKL we apply law of sines

\frac{SinK}{JL} = \frac{SinJ}{KL} = \frac{SinL}{JK}

Now we take \frac{SinK}{JL}  = \frac{SinJ}{2.3}

\frac{Sin67}{JL} = \frac{Sin39*}{2.3}

JL = \frac{(2.3)Sin67}{Sin39}

\frac{(2.3)(0.92)}{(0.6293)} = 3.36 units

Now \frac{SinL}{JK} = \frac{SinJ}{KL}

\frac{Sin74}{JK} = \frac{Sin39}{2.3}

JK = \frac{2.3(Sin74)}{(Sin39)}

    = \frac{2.3(0.9613)}{(0.6293)}

    = 3.51 units

So perimeter of the triangle = 3.36 + 3.51 + 2.3 = 9.15 units ≈ 9.2 units.

Option D is the answer.

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Find the coordinates of the midpoint of line AB given the coordinates: A(-1,<br> 5) B(2,-3)*<br> 
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Answer:

              \bold{M_{AB}\left(\frac12\,,\ 1\right)}

Step-by-step explanation:

The midpoint of AB coordinates are:  M_{AB}\left(x_M\,,\ y_M\right)  where:

x_M=\frac{x_A+x_B}2=\frac{-1+2}2=\frac12\\\\y_M=\frac{y_A+y_B}2=\frac{5+(-3)}2=\frac{2}2=1

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3 years ago
△STR≅△LMN, SR=7b+8, and LN=11b−12. Find b and SR.
Goryan [66]

Given:

\Delta STR\cong \Delta LMN

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LN=11b-12

To find:

The value of b and SR.

Solution:

We have,

\Delta STR\cong \Delta LMN                          (Given)

ST\cong LN                                  (CPCTC)

ST=LN

Substituting the given values, we get

7b+8=11b-12

7b-11b=-8-12

-4b=-20

Divide both sides by -4.

\dfrac{-4b}{-4}=\dfrac{-20}{-4}

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SR=7(5)+8

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Step-by-step explanation:

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2 years ago
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