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laila [671]
3 years ago
7

triangle qrs has the angle measures shown. m∠q = (1x)° m∠r = (3x)° m∠s = (6x)° the measure of the obtuse angle equals

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
7 0
The sum of all interior angles in a triangle is 180°.

m∠q + m∠r + m∠s = 180°
1x + 3x + 6x = 180
10x = 180
x = 180/10
x = 18

m∠q = (1x)° = 1 x 18 = 18°
m∠ r = (3x)° = 3 x 18 = 54°
m∠s = (6x)° = 6 x 18 = 108°

m∠s is the obtuse angle because its measure is more than 90°. Its angle measures 108°
77julia77 [94]3 years ago
4 0

Answer:108

Step-by-step explanation:

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7 + 24 .3<br> 31<br> 55<br> c<br> 96<br> 112
GaryK [48]

Answer:

The answer is 325.3

Step-by-step explanation:

I hope this helped I used a calculator sorry if I'm late and I hope this isn't wrong

7 0
2 years ago
What is the area of Figure ABCD?
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66 square inches
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8 0
3 years ago
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6. Identify the recursive formula for the sequence 3, –15, 75, –375, . . .
vlada-n [284]

Answer:

first option

Step-by-step explanation:

There is a common ratio r between consecutive terms in the sequence, that is

r = - 15 ÷ 3 = 75 ÷ - 15 = - 375 ÷ 75 = - 5

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f(n) = - 5f(n - 1) if n > 1

with f(1) = 3 ← first term

4 0
3 years ago
You increase the size of a page by 30%. Then you decrease it by 30%. What is the size of the page now?
kotegsom [21]
Lets use 1 to solve this problem because it is easiest to show. 

Multiply 1 by 1.3 for a 30% increase (1*1.3=1.3). 

Then multiply 1.3 by .7 for a 30% decrease. (1.3*.7=.91)  

Therefore the page had a 9% reduction from its original size or is 91% of its original size. 
8 0
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In a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Interne
Dvinal [7]

Answer:

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

Step-by-step explanation:

Given that in a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week. The mean of the sample observations was 12.9 hours.

H_0: \bar x =12.7\\H_a: \bar x >12,7

(Right tailed test at 5% level)

Mean difference = 0.2

Std error = \frac{6}{\sqrt{1000} } \\=0.1897

Z statistic = 1.0540

p value = 0.145941

since p >alpha we do not reject H0.

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

5 0
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