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3 years ago

triangle qrs has the angle measures shown. m∠q = (1x)° m∠r = (3x)° m∠s = (6x)° the measure of the obtuse angle equals

2 answers:

7 0

The sum of all interior angles in a triangle is 180°.

m∠q + m∠r + m∠s = 180°
1x + 3x + 6x = 180
10x = 180
x = 180/10
x = 18

m∠q = (1x)° = 1 x 18 = 18°
m∠ r = (3x)° = 3 x 18 = 54°
m∠s = (6x)° = 6 x 18 = 108°

m∠s is the obtuse angle because its measure is more than 90°. Its angle measures 108°

77julia77 [94]3 years ago

4 0

Answer:108

Step-by-step explanation:

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Correct answers only!

malfutka [58]

Answer:

$60.5

Step-by-step explanation:

Simply plug in all known values to the equation. You know that p is 50, r is 0.10, and t is 2, for two years. After you plug in all those values, you can solve for this equation, and get 60.5 as your answer.

4 0

2 years ago

g If A and B are disjoint events, with P( A) = 0.20 and P( B) = 0.30. Then P( A and B) is: a. .00 b. .10 c. .50 d. 0.06

Lostsunrise [7]

Answer: A) 0

P(A and B) = 0 when events A and B are disjoint, aka mutually exclusive.

We say that two events are mutually exclusive if they cannot happen at the same time. An example would be flipping a coin to have it land on heads and tails at the same time.

8 0

3 years ago

Write an equivalent expression to present patricia total earnings this week 7h + 135 + 5h = ?h + ?

Paul [167]

Answer: 12 h + 135

Step-by-step explanation: 7h +135 + 5h = ?h + ?

7h +5h +135

=12h +135

So u combine like terms together which are 7h and 5h which gives you 12 h.And then you have 135 left,so you add 12h to 135.

Ps.If you don't know what like terms are.I will explain down below.

Like terms are variable that are the same.For an example 4y and 3y are like terms .Another example is 1/3 xy and 6xy .

Hope this helps :) and if it does please give brainliest .

8 0

2 years ago

Trina uses 8.6 pints of blue paint and white paint to paint her bedroom walls.

max2010maxim [7]

<h3>Trina uses 3.44 or $\frac{ 17.2}{5}$ pints of white paint</h3>

<em><u>Solution:</u></em>

Given that,

Trina uses 8.6 pints of blue paint and white paint to paint her bedroom walls

3/5 of the amount is blue paint, and the rest is white paint

From given,

3/5 of 8.6 pints is blue paint

$Remaining = 1 - \frac{3}{5}\\\\Remaining = \frac{2}{5}$

Thus, 2/5 of 8.6 pints is white paint

<em><u>How many pints of white paint did she use to paint her bedroom walls? </u></em>

$White\ paint = \frac{2}{5} \times 8.6\\\\White\ paint = \frac{17.2}{5}\\\\White\ paint = 3.44$

Thus she uses 3.44 or 17.2/5 pints of white paint

5 0

2 years ago

The probability that two people have the same birthday in a room of 20 people is about 41.1%. It turns out that

salantis [7]

Answer:

a) Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

b) We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Part a

Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

Part b

We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

4 0

3 years ago