We know that
tan 32°=opposite side/adjacent side
[adjacent side]=[opposite side]/tan 32°
in this problem
opposite side-----> will be the altitude of the flock of birds minus your eye level above the ground
(12000-6)-----> 11994 ft
adjacent side------->will be the horizontal distance between you and the birds
32°------> <span>an angle of elevation
</span>
[adjacent side]=[11994]/tan 32°-------> 19194.41 ft
the answer is
<span>The horizontal distance from the birds is 19194.41 ft</span>
Withdraw- remove
Deposit- put
Discount- take off
I believe it is 64 cm squared
<u>Correct </u><u>Inputs </u><u>:-</u>
In ΔABC right angled at A, D and E are points on BC, C such that BD = CD and AD ⊥ BC
Let us know about definition of altitude first. The altitude of a triangle is the perpendicular line segment drawn from the vertex to the opposite side of the triangle.
Median is the line segment from a vertex to the midpoint of the opposite side.
<u>Let us Check all options one by one </u>
- CD is line segment which starts from vertex C but don't falls on opposite side AB thus it is not an altitude.❌
- BA is line segment which starts from vertex B and falls perpendicularly on opposite sides AC and is thus an altitude.✔️
- AD is line segment which starts from vertex A and falls perpendicularly on opposite side BC and is thus an altitude.✔️
- AE is a line segment which starts from vertex A but doesn't falls perpendicularly on opposite side BC and is thus not an altitude.❌
- AD falls on BC with D as mid point because BD = CD and is thus a median. ✔️
I jus need points so but I’m doing the same thing so I think it’s 3
