Answer:
11
Step-by-step explanation:
Rewrite expression using given information:
20 - 3a + 2b = 20 - 3*7 + 2*6
20 - 21 + 12 = 11
Answer:
There are 35 possible group of 3 socks from a total of 7
Step-by-step explanation:
Given
Number of unique socks = 7
Number of possible selection = 3
Required
Number of ways she can make her selection.
The question can be categorised as combination; reason being that words like "take" as used in the question points to combination or selection.
To solve this, we make use of combination formula.
nCr = nPr/r!
Where n = 7 and r = 3
By substitution, we have
7C3 = 7P3÷3!
Taking it one at a time
7P3 = 7!÷(7-3)!
7P3 = 7! ÷ 4!
7P3 = 7 * 6 * 5 * 4! ÷ 4!
7P3 = 7 * 6 * 5
7P3 = 210
3! = 3 * 2 * 1
3! = 6.
So,
7C3 = 210 ÷ 6
7C3 = 35.
Hence, there are 35 possible group of 3 socks from a total of 7
Answer:
116.3, 41.05
Step-by-step explanation:
Using the growth rate formula
Final = initial(1 + rate)^n
Rate = 2% = 0.02
n = number of years
Carry capacity = 100%( the original state before the disease)=final
100% = 1
1 = 0.1 ( 1+0.02)^n
10 = (1.02) ^n
Log 10/ Log 1.02 = 116.3 = n
b) initial rate doubled = 0.02*2 (2%*2) = 0.04
Initial population doubled by importation = 0.1 *2 = 0.2
Again, 1 = 0.2 ( 1+0.04)^n
5 = 1.04^n
Log 5/ Log 1.04 = 41.05 = n
There were 340,000 cattle placed on feed
How many of the 340,000 cattle placed on feed were between 700 and 799 pounds?
Given the fraction of total cattle for 700 - 799 pounds is 2/5
Let x be the number of cattle between 700 - 799 pounds
We make a proportion using the fraction
Cross multiply it and solve for x
340000* 2 = 5x
680000 = 5x
Divide by 5 on both sides
So x= 136,000
There were 136,000 cattle between 700 and 799 pounds
