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Nikitich [7]
2 years ago
6

The figure below has what type of symmetry?

Mathematics
1 answer:
vodomira [7]2 years ago
7 0

Answer:

c both point and line symmetry.

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Write the equation of the line that passes through the points (-2,0) and (1,2).
Ierofanga [76]

Answer:

y = 2/3x + 1 1/3

Step-by-step explanation:

Find the slope using rise over run, (y2 - y1) / (x2 - x1)

Plug in the points:

(y2 - y1) / (x2 - x1)

(2 - 0) / (1 + 2)

2 / 3

= 2/3

Then, plug in the slope and a point into y = mx + b to solve for b:

y = mx + b

2 = 2/3(1) + b

2 = 2/3 + b

1 1/3 = b

Plug in the slope and y intercept into y = mx + b

y = 2/3x + 1 1/3 is the equation of the line

5 0
3 years ago
HELP NEEDED ASAP MATHS PLEASE!!!
BabaBlast [244]
You plug in the values for x in each respective equation.

a) f(3) = 3 + 1 which equals: 4.
so, f(3) = 4

b) g(3) = (3)^2 - 3 which equals 9 - 3, which equals 6.
so, g(3) = 6.

hope this helps! (:
5 0
3 years ago
Can someone please answer this for me and with solution and "Checking"( to see if your answer is correct) please.​
mamaluj [8]

Answer:

√9/√13=5

√10-3r=r

Step-by-step explanation:

this must be the answer

4 0
3 years ago
Represent the arithmetic series using the recursive formula. 94, 89, 84, 79, … <br>pLeAsE hUrRy
andreev551 [17]

Answer:

The answer is 5

Step-by-step explanation:

Hope it helps <3 c:

6 0
2 years ago
A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess
maxonik [38]

Answer:

Total weight of the wheat placed on 45th square will be = 1.26\times 10^{6}tons

Step-by-step explanation:

King rewarded the inventor of chess by giving grain of wheat on every square of the chess board. He places one  grain of wheat on first square, 2 on second, 4 on 3rd, 8 on 4th and so on.

In fact he places grains of wheat in a progression S = 1, 2, 4, 8, 16.........n terms where value of n is 64.

We can rewrite the progression as S = 2°, 2, 2², 2³,.........n terms (n = 64)

In a geometric progression we know the nth term = a(r^{n-1})

where a = first term of the series, r = common ratio, n = number of terms

Now we have to calculate the weight of all wheat placed on 45th square.

So we will put the values in the given formula 45th term =

1\times (2^{45-1}) = 2^{44}=1.76\times 10^{13}

Then the weight of wheat will be = 2.51\times 10^{9}pounds=1.26\times 10^{6}tons



7 0
3 years ago
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