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Reptile [31]
3 years ago
15

The products of respiration are the_____

Mathematics
1 answer:
SpyIntel [72]3 years ago
4 0

Step-by-step explanation:

Powerhouse of photo synthesis

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Which is greater 4/5 or 3/4? Explain how you know
GuDViN [60]

Answer:

4/5>3/4

Step-by-step explanation:

4/5=0.8

3/4=0.75

4/5 is grater than 3/4 by 0.5

I hope this helps!

6 0
3 years ago
2x/3x^3 in a simplest form?
ASHA 777 [7]

Answer:

2/3x^2

Step-by-step explanation:

5 0
3 years ago
How would you classify the number 121?
Dahasolnce [82]

Answer:

121 is a rational number, a perfect square.

Step-by-step explanation:

I know its a short answer, but I hope it helps.

8 0
3 years ago
A high school guidance counselor determined the following information regarding students and their likelihood of playing a sport
iogann1982 [59]

Conditional Probability

Given two events A and B (not excluding), the probability that A occurs given that B has occurred is called a <em>conditional probability</em> and is calculated as:

P(A|B)=\frac{P(A\cap B)}{P(B)}

Where P(A∩B) is the probability that A and B occur simultaneously and P(B) is the probability that B occurs.

Now with the given data, we must find the values of the required probabilities.

30% of the students play a sport (S), this means that:

70% of the students don't play a sport (NS).

65% of the students have a job.

Note that there could be students who both play sports and have a job.

Of the 30% of the students who play a sport, 50% have a job. This means that:

15% of the students play a sport and don't have a job

15% of the students play a sport AND have a job

65% - 15% = 50% of the students have a job and don't play a sport

That last number is the numerator of the equation given above:

P(A∩B) = 0.5

The event B corresponds to students that don't play a sport (NS), thus:

P(B) = 0.7

Thus we have:

P(A|B)=\frac{0.5}{0.7}=\frac{5}{7}

The required probability is 5/7 or 0.7143

4 0
1 year ago
a 29 gram sample of a substance that's used to preserve fruits and vegetables has a k-value of 0.1359. Find the substance's half
kaheart [24]
Okay well
a(t)= amount of substance remaining after t days
assuming exponential decay, a(t)=29e^-0.1359t

now, find the half, set a(t)= half the original and solve for t

14.5=29e^-0.1359t
0.5=e^-0.1359t
In(0.5)=In(e^-0.1359t)
In(0.5)=-o.1359t

t=in(0.5)/(-0.1359)= (aprox) 5.1 days

6 0
4 years ago
Read 2 more answers
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