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lianna [129]
3 years ago
10

Solve the following system of equations by the substitution method. 2x = 10y - 8 3x + 4y + 5 = 0

Mathematics
1 answer:
Natali [406]3 years ago
5 0

Answer:

x = -\frac{41}{19}

y = \frac{7}{19}

Step-by-step explanation:

2x = 10y - 8

3x + 4y + 5 = 0

2x = 10y - 8

x = 5y - 4

3x + 4y + 5 = 0

3 ( 5y - 4 ) + 4y + 5 = 0

19y - 7 = 0

19y = 7

y = \frac{7}{19}

x = 5y - 4

x = 5 ( \frac{7}{19} ) - 4

x = -\frac{41}{19}

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Answer:

  c)  (-5, -7)

Step-by-step explanation:

In a parallelogram, the midpoints of the diagonals are the same point. This means ...

  (R+T)/2 = (S+U)/2

  R +T -S = U

  (-6 +4 -3, -3 -1 -3) = U = (-5, -7)

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3 years ago
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Simplify completely: 8x+4/x^3+23÷4x^2-10x-6/9-x^2
Helen [10]

Answer:

The simplified form is: -x^2-2x+\frac{4}{x^3}+\frac{23}{4x^2}-\frac{2}{3}

Step-by-step explanation:

To simplify the expression given we, need to open the brackets, and if there is power term. Then we need to group all the like terms and then arrange in the descending order of powers of the given expression.

Now the expression that is given to us is:

8x+\frac{4}{x^3}+\frac{23}{4x^2}-10x-\frac{6}{9}-x^2

Here we will simplify it by grouping the like terms, as follows:

8x+\frac{4}{x^3}+\frac{23}{4x^2}-10x-\frac{6}{9}-x^2\\=-x^2+8x-10x+\frac{4}{x^3}+\frac{23}{4x^2}-\frac{6}{9}=-x^2-2x+\frac{4}{x^3}+\frac{23}{4x^2}-\frac{2}{3}

So this is the required simplified form.

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3 years ago
You divide a number and get a remainder of 4. what 1 - digit number can the divisor of the problem?
ahrayia [7]

Answer:

<em>Any of the numbers 5,6,7,8,9 could be the divisor of the problem.</em>

Step-by-step explanation:

<u>Division</u>

If I divide a number and get a remainder of 4, then the divisor must be greater than 4. A divisor of 4, for example, would lead to a remainder of (maximum) 3.

Thus, our divisor can only be one among the numbers: 5,6,7,8,9. If the dividend is exactly 4, then the divisions

4/5, 4/6, 4/7, 4/8, and 4/9

they all produce the same remainder of 4.

Thus, any of the numbers 5,6,7,8,9 could be the divisor of the problem

6 0
4 years ago
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