Question

Solve the following system of equations by the substitution method. 2x = 10y - 8 3x + 4y + 5 = 0

Answer 1

Answer:

x = $-\frac{41}{19}$

y = $\frac{7}{19}$

Step-by-step explanation:

2x = 10y - 8

3x + 4y + 5 = 0

2x = 10y - 8

x = 5y - 4

3x + 4y + 5 = 0

3 ( 5y - 4 ) + 4y + 5 = 0

19y - 7 = 0

19y = 7

y = $\frac{7}{19}$

x = 5y - 4

x = 5 ( $\frac{7}{19}$ ) - 4

x = $-\frac{41}{19}$