Answer:
verdical lines have an undefined slope so it might be 4
Answer
n>- 19/33
1 Simplify 10n+4-n10n+4−n to 9n+49n+4.
1+4(-6n-4)<9n+41+4(−6n−4)<9n+4
2 Expand.
1-24n-16<9n+41−24n−16<9n+4
3 Simplify 1-24n-161−24n−16 to -24n-15−24n−15.
-24n-15<9n+4−24n−15<9n+4
4 Add 24n24n to both sides.
-15<9n+4+24n−15<9n+4+24n
5 Simplify 9n+4+24n9n+4+24n to 33n+433n+4.
-15<33n+4−15<33n+4
6 Subtract 44 from both sides.
-15-4<33n−15−4<33n
7 Simplify -15-4−15−4 to -19−19.
-19<33n−19<33n
8 Divide both sides by 3333.
-\frac{19}{33}<n−
33
19
<n
9 Switch sides.
n>-\frac{19}{33}n>−
33
19
Done
The third term, fourth term and tenth term are -1, -3, -15 respectively.
<h3>
What is a sequence?</h3>
A sequence is a pattern of numbers in which successive terms differ by an constant term called the common difference or ratio.
Analysis:
For a sequence defined by the rule A(n) = 3 + (n-1)(-2)
Third term, n = 3
A(3) = 3 + (3-1)(-2) = -1
Fourth term, n = 4
A(4) = 3 + (4-1)(-2) = -3
Tenth term, n = 10
A(10) = 3 + (10-1)(-2) = -15
In conclusion, the third, fourth, tenth terms are -1, -3 and -15 respectively.
Learn more about sequence: brainly.com/question/6561461
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Answer:
x = 31.8
Step-by-step explanation:
From the picture attached,
By applying Pythagoras theorem in right ΔADC,
AC² = AD² + CD²
(22)² = AD² + (16)²
AD² = 484 - 256
AD = √228
= 2√57
Now we apply Pythagoras theorem in right ΔADB,
AB² = AD² + DB²
x² = 228 + (44 - 16)²
x² = 228 + 784
x² = 1012
x = √1012
= 31.81
≈ 31.8