Answer:
Step-by-step explanation:
hello :
the diameter = 2× radius = 2× 1=2unit
Answer:
a
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
y = -6x-8
Step-by-step explanation:
Answer with Step-by-step explanation:
We are given that
Height of radio tower =650 ft
From figure
AB=650 ft
BC=180 ft
We have to find the AC.
Using cosine law:
![c=\sqrt{a^2+b^2-2ab cos\alpha}](https://tex.z-dn.net/?f=c%3D%5Csqrt%7Ba%5E2%2Bb%5E2-2ab%20cos%5Calpha%7D)
![AC=\sqrt{(650)^2+(180)^2-2\times 650\times 180\times cos 80^{\circ}}](https://tex.z-dn.net/?f=AC%3D%5Csqrt%7B%28650%29%5E2%2B%28180%29%5E2-2%5Ctimes%20650%5Ctimes%20180%5Ctimes%20cos%2080%5E%7B%5Ccirc%7D%7D)
![c=643.64 ft](https://tex.z-dn.net/?f=c%3D643.64%20ft)
Hence, a guy required 643.64 ft wire when it is to connect to the tower and be secured at a point on the sloped side 180 ft from the base of the tower.
b.In a right triangle ABC, AB=![\frac{650}{2}=325 ft](https://tex.z-dn.net/?f=%5Cfrac%7B650%7D%7B2%7D%3D325%20ft%20)
Pythagorous theorem :![(Hypotensuse)^2=(perpendicular\;side)^2+(base)^2](https://tex.z-dn.net/?f=%28Hypotensuse%29%5E2%3D%28perpendicular%5C%3Bside%29%5E2%2B%28base%29%5E2)
Substitute the values
![(AC)^2=(AB)^2+(BC)^2](https://tex.z-dn.net/?f=%28AC%29%5E2%3D%28AB%29%5E2%2B%28BC%29%5E2)
![(AC)=\sqrt{(325)^2+(180)^2}](https://tex.z-dn.net/?f=%28AC%29%3D%5Csqrt%7B%28325%29%5E2%2B%28180%29%5E2%7D)
![AC=371.52 ft](https://tex.z-dn.net/?f=AC%3D371.52%20ft%20)
Hence, the length of wire should be 371.52 ft when a second guy connect the middle of the tower and be secured at a point 180 ft from the base on the flat side by wire.