If B went from (1, 5) to (-3, 2), that means it was shifted down 4 units and left 3 units. So for each of the other points, we subtract 4 from the x value, and subtract 3 from the y value. Point A is (-3, -4), moving this by subtracting 4 from x and 3 from y, we get A'(-7, -7). Point C was (4, 1), subtract 4 and 3, leaving C'(0, -2).
So A'(-3, -4), B'(-3, 2) and C'(0, -2)
N/2+5=3
move +5 to the other side
sign changes from +5 to -5
N/2+5-5= 3-5
N/2= -2
Mutiply both sides by 2/1
N/2*2/1 - Cross out 2 and 2 , divide by 2 then becomes N
-2(2)/1= -4/1= -4
N= -4
Answer : N= -4
Answer:
1.97
Step-by-step explanation:
4.82 - 2.85 = 1.97
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Answer:
Step-by-step explanation:
Method 1: Taking the log of both sides...
So take the log of both sides...
5^(2x + 1) = 25
log 5^(2x + 1) = log 25 <-- use property: log (a^x) = x log a...
(2x + 1)log 5 = log 25 <-- distribute log 5 inside the brackets...
(2x)log 5 + log 5 = log 25 <-- subtract log 5 both sides of the equation...
(2x)log 5 + log 5 - log 5 = log 25 - log 5
(2x)log 5 = log (25/5) <-- use property: log a - log b = log (a/b)
(2x)log 5 = log 5 <-- divide both sides by log 5
(2x)log 5 / log 5 = log 5 / log 5 <--- this equals 1..
2x = 1
x=1/2
Method 2
5^(2x+1)=5^2
2x+1=2
2x=1
x=1/2
