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2 years ago

Help me please this is the last question there may be more coming

Mathematics

2 answers:

Natasha2012 [34]2 years ago

8 0

Answer:

Where is your stuff/work???

Step-by-step explanation:

Mariana [72]2 years ago

4 0

Answer:

I dont see the picture sry

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What is 6 percent of 1,600,00 dollars

yarga [219]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

convert the measurement 5,000 yards (There are 1.09 yards in a meter.) A. 4000 m B. 6000 m C. 5 km D. 500 m

Ray Of Light [21]

Answer:

Step-by-step explanation:

If 1.09 yards is in a meter, then there are 4572 meters in 5000 feet.

A is the correct answer. Hope this helps!

3 0

2 years ago

Scientists modeled the intensity of the sun, I, as a function of the number of hours since 6:00 a.m., h, using the

MAVERICK [17]

The functions are illustrations of composite functions.

<em>The soil temperature at 2:00pm is 67</em>

The given parameters are:

$\mathbf{I(h) =\frac{12h - h^2}{36}}$ ---- the function for sun intensity

$\mathbf{T(I) =\sqrt{5000I}}$ -- the function for temperature

At 2:00pm, the value of h (number of hours) is:

$\mathbf{h = 2:00pm - 6:00am}$

$\mathbf{h = 8}$

Substitute 8 for h in $\mathbf{I(h) =\frac{12h - h^2}{36}}$ , to calculate the sun intensity

$\mathbf{I(8) =\frac{12 \times 8 - 8^2}{36}}$

$\mathbf{I(8) =\frac{32}{36}}$

$\mathbf{I(8) =\frac{8}{9}}$

Substitute 8/9 for I in $\mathbf{T(I) =\sqrt{5000I}}$ , to calculate the temperature of the soil

$\mathbf{T(8/9) =\sqrt{5000 \times 8/9}}$

$\mathbf{T(8/9) =\sqrt{4444.44}}$

$\mathbf{T(8/9) =66.67}$

Approximate

$\mathbf{T(8/9) =67}$

Hence, the soil temperature at 2:00pm is 67

Read more about composite functions at:

brainly.com/question/20379727

5 0

2 years ago

Is 3/10 of the visitors were adults and there were 100 visitors how many visitors were adults?

e-lub [12.9K]

So, 3/10 = 100/x $\frac{3}{10}= \frac{100}{x} 3x=100(10) 3x=1000 1000/3 = 333.33=x$

5 0

2 years ago

4. a) A ping pong ball has a 75% rebound ratio. When you drop it from a height of k feet, it bounces and bounces endlessly. If t

Klio2033 [76]

First part of question:

Find the general term that represents the situation in terms of k.

The general term for geometric series is:

$a_{n}=a_{1}r^{n-1}$

$a_{1}$ = the first term of the series

$r$ = the geometric ratio

$a_{1}$ would represent the height at which the ball is first dropped. Therefore:

$a_{1} = k$

We also know that the ball has a rebound ratio of 75%, meaning that the ball only bounces 75% of its original height every time it bounces. This appears to be our geometric ratio. Therefore:

$r=\frac{3}{4}$

Our general term would be:

$a_{n}=a_{1}r^{n-1}$

$a_{n}=k(\frac{3}{4}) ^{n-1}$

Second part of question:

If the ball dropped from a height of 235ft, determine the highest height achieved by the ball after six bounces.

$k$ represents the initial height:

$k = 235\ ft$

$n$ represents the number of times the ball bounces:

$n = 6$

Plugging this back into our general term of the geometric series:

$a_{n}=k(\frac{3}{4}) ^{n-1}$

$a_{n}=235(\frac{3}{4}) ^{6-1}$

$a_{n}=235(\frac{3}{4}) ^{5}$

$a_{n}=55.8\ ft$

$a_{n}$ represents the highest height of the ball after 6 bounces.

Third part of question:

If the ball dropped from a height of 235ft, find the total distance traveled by the ball when it strikes the ground for the 12th time. 

This would be easier to solve if we have a general term for the <em>sum </em>of a geometric series, which is:

$S_{n}=\frac{a_{1}(1-r^{n})}{1-r}$

We already know these variables:

$a_{1}= k = 235\ ft$

$r=\frac{3}{4}$

$n = 12$

Therefore:

$S_{n}=\frac{(235)(1-\frac{3}{4} ^{12})}{1-\frac{3}{4} }$

$S_{n}=\frac{(235)(1-\frac{3}{4} ^{12})}{\frac{1}{4} }$

$S_{n}=(4)(235)(1-\frac{3}{4} ^{12})$

$S_{n}=910.22\ ft$

8 0

2 years ago