Answer:
ok so i think your gonna haveto use addition tell me if im wrong
Step-by-step explanation:you have a blessed thanksgiveing
Answer:
![t \leq 18.67\ years](https://tex.z-dn.net/?f=t%20%5Cleq%2018.67%5C%20years)
Step-by-step explanation:
we know that
The simple interest formula is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest
t is Number of Time Periods
in this problem we have
The inequality that represented this situation is
![P(1+rt) \leq A](https://tex.z-dn.net/?f=P%281%2Brt%29%20%5Cleq%20A)
substitute the values and solve for t
![4,500(1+0.03t) \leq 7,020](https://tex.z-dn.net/?f=4%2C500%281%2B0.03t%29%20%5Cleq%207%2C020)
![(0.03t) \leq (7,020/4,500)-1](https://tex.z-dn.net/?f=%280.03t%29%20%5Cleq%20%287%2C020%2F4%2C500%29-1)
![t \leq [(7,020/4,500)-1]/0.03](https://tex.z-dn.net/?f=t%20%5Cleq%20%5B%287%2C020%2F4%2C500%29-1%5D%2F0.03)
![t \leq 18.67\ years](https://tex.z-dn.net/?f=t%20%5Cleq%2018.67%5C%20years)
First we need the distances of the sides of the polygon, because perimeter = sum of all sides.
![d = \sqrt{{(y2 - y1)}^{2} + {(x2 - x1)}^{2} }](https://tex.z-dn.net/?f=d%20%3D%20%20%5Csqrt%7B%7B%28y2%20-%20y1%29%7D%5E%7B2%7D%20%2B%20%7B%28x2%20-%20x1%29%7D%5E%7B2%7D%20%7D%20)
![d1 = \sqrt{{(1 - 4)}^{2} + {( - 2 - - 2)}^{2} } \\ = \sqrt{{(- 3)}^{2} + {(0)}^{2} } = \sqrt{9} \: = 3](https://tex.z-dn.net/?f=d1%20%3D%20%20%5Csqrt%7B%7B%281%20-%204%29%7D%5E%7B2%7D%20%2B%20%7B%28%20-%202%20-%20%20-%202%29%7D%5E%7B2%7D%20%7D%20%5C%5C%20%20%3D%20%20%5Csqrt%7B%7B%28-%203%29%7D%5E%7B2%7D%20%2B%20%7B%280%29%7D%5E%7B2%7D%20%7D%20%3D%20%20%5Csqrt%7B9%7D%20%20%5C%3A%20%3D%203)
![d2 = \sqrt{{(4 - 7)}^{2} + {( - 2 - 2)}^{2} } \\ = \sqrt{{(- 3)}^{2} + {( -4)}^{2} } = \sqrt{9 + 16} \\ = \sqrt{25} \: = 5](https://tex.z-dn.net/?f=d2%20%3D%20%5Csqrt%7B%7B%284%20-%207%29%7D%5E%7B2%7D%20%2B%20%7B%28%20-%202%20-%202%29%7D%5E%7B2%7D%20%7D%20%5C%5C%20%20%3D%20%5Csqrt%7B%7B%28-%203%29%7D%5E%7B2%7D%20%2B%20%7B%28%20-4%29%7D%5E%7B2%7D%20%7D%20%3D%20%20%5Csqrt%7B9%20%2B%2016%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B25%7D%20%20%5C%3A%20%3D%205)
![d3 \: = \sqrt{{(7 - 4)}^{2} + {(2 - 6)}^{2} } \\ = \sqrt{{(3)}^{2} + {( - 4)}^{2} } = \sqrt{9 + 16} \\ = \sqrt{25} \: = 5](https://tex.z-dn.net/?f=d3%20%5C%3A%20%3D%20%5Csqrt%7B%7B%287%20-%204%29%7D%5E%7B2%7D%20%2B%20%7B%282%20-%206%29%7D%5E%7B2%7D%20%7D%20%5C%5C%20%20%3D%20%20%5Csqrt%7B%7B%283%29%7D%5E%7B2%7D%20%2B%20%20%7B%28%20-%204%29%7D%5E%7B2%7D%20%7D%20%3D%20%20%5Csqrt%7B9%20%2B%2016%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B25%7D%20%5C%3A%20%20%3D%205)
![d4 = \sqrt{{(4 - 1)}^{2} + {(6 - 6)}^{2} } \\ = \sqrt{ {(3)}^{2} + {(0)}^{2} } = \sqrt{9} \: = 3](https://tex.z-dn.net/?f=d4%20%3D%20%5Csqrt%7B%7B%284%20-%201%29%7D%5E%7B2%7D%20%2B%20%7B%286%20-%206%29%7D%5E%7B2%7D%20%7D%20%5C%5C%20%20%3D%20%20%5Csqrt%7B%20%7B%283%29%7D%5E%7B2%7D%20%2B%20%20%7B%280%29%7D%5E%7B2%7D%20%20%7D%20%20%3D%20%20%5Csqrt%7B9%7D%20%5C%3A%20%20%3D%203)
![d5 = \sqrt{{(1 - 1)}^{2} + {(-2 - 6)}^{2} } \\ = \sqrt{ {(0)}^{2} + {( - 4)}^{2}} = \sqrt{16} \: = 4](https://tex.z-dn.net/?f=d5%20%3D%20%5Csqrt%7B%7B%281%20-%201%29%7D%5E%7B2%7D%20%2B%20%7B%28-2%20-%206%29%7D%5E%7B2%7D%20%7D%20%20%5C%5C%20%3D%20%20%5Csqrt%7B%20%7B%280%29%7D%5E%7B2%7D%20%2B%20%20%7B%28%20-%204%29%7D%5E%7B2%7D%7D%20%3D%20%20%5Csqrt%7B16%7D%20%20%5C%3A%20%20%3D%204%20)
Now, we add all sides for the perimeter:
p = d1 + d2 + d3 + d4 + d5
p = 3+5+5+3+4 = 20 units
Answer:
1.33
Step-by-step explanation: