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S_A_V [24]
3 years ago
6

Angle bisectors AX and of triangle ABC meet at point I. Find angle C in degrees, if AIB = 109.

Mathematics
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer:

angle C = 38 degrees

Step-by-step explanation:

Refer to attached figure (sorry, forgot to attach earlier)

Given

AIB = 109

Let

CAX = XAB = x

CBY = YBA = y

XIB = YIA = x+y    ........exterior angles

XIB = YIA = 180-109 = 71   ............ sum of angles on a line

=>

x+y = 71

ACB = 180 - 2x -2y  ................. sum of angles of a triangle

= 180 - 2(x+y)

= 180 - 2(71)

= 180 - 142

= 38

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