All categories

3 years ago

What is 8.1% of 18.43

Mathematics

1 answer:

IrinaK [193]3 years ago

5 0

9514 1404 393

Answer:

1.49283

Step-by-step explanation:

8.1% as a decimal is 0.081

The product of that and 18.43 is ...

0.081 × 18.43 = 1.49283

If this is a monetary value, it would round to 1.49.

You might be interested in

One canned juice drink is 25%orange juice; another is 10%orange juice. how many liters of each should be mixed together in or

sertanlavr [38]

   Qty    · % = Total
Drink 1:    x .25 = .25x
Drink 2:   15 - x .10 = .10(15 - x)
Mixture: 15 .21 = .25x + .10(15 - x)

   (15)(.21)   =    .25x + 1.5 - .10x
   3.15 =    .15x + 1.5
   1.65 = .15x
   11    = x

Drink 1 (25%) is 11 liters
Drink 2 (10%) is 15 - 11 = 4 liters

6 0

3 years ago

In March 2007, Business Week reported that at the top 50 business schools, students studied an average of 14.6 hours. You wonder

Rasek [7]

Answer:

The hypotheses used in this situation

$H_0:\mu = 14.6$

$H_a:\mu \neq 14.6$

Step-by-step explanation:

We are given that Business Week reported that at the top 50 business schools, students studied an average of 14.6 hours.

Mean = $\mu = 14.6$

Claim : The amount UMSL students study is different from this 14.6 hour benchmark.

The hypotheses used in this situation

$H_0:\mu = 14.6$

$H_a:\mu \neq 14.6$

5 0

3 years ago

-14n + q=rt-4n, for n

pentagon [3]

N = -1/10rt + 1/10q
= −14n+q+4n=rt−4n+4n
= −10n+q=rt
= −10n+q+−q=rt+−q
= −10n=rt−q
= -10n/-10 = rt-q/-10
So the answer is:
= n = -1/10rt + 1/10q

3 0

3 years ago

Read 2 more answers

Can someone please tell me whats the best way to do good on a state test

zhenek [66]

Take online tests on what you think you need work on
And also study

3 0

3 years ago

The circle given by : x^2 + y^2 - 6y - 12 = 0 can be written as:

deff fn [24]

Step-by-step explanation:

Given equation of circle is,

${x}^{2} + {y}^{2} - 6y - 12 = 0 \\ by \: compairing \: it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\2 g = 0 \: or \: g = 0 \\ 2f= - 6 \\ or \: f= - 3 \\ c = - 12$

again the another form of circle is,

${x}^{2} + {(y - k)}^{2} = 21 \\ or \: {x}^{2} + {y}^{2} - 2ky + {k}^{2} - 21 = 0 \\ by \: compairing \:it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\ g = 0 \\f = - k \\ c = {k}^{2} - 21$

now equating the values of f in both equations,

-k=-3

i.e. k=3

therefore k=3

4 0

3 years ago